# [Tutor] recursive problem

Shashwat Anand anand.shashwat at gmail.com
Thu Sep 9 13:59:43 CEST 2010

```On Thu, Sep 9, 2010 at 3:11 PM, Roelof Wobben <rwobben at hotmail.com> wrote:

>
>
> ------------------------------
> From: anand.shashwat at gmail.com
> Date: Thu, 9 Sep 2010 15:08:10 +0530
> Subject: Re: [Tutor] recursive problem
> To: rwobben at hotmail.com
> CC: tutor at python.org
>
>
>
> On Thu, Sep 9, 2010 at 2:21 PM, Roelof Wobben <rwobben at hotmail.com> wrote:
>
> Hello,
>
> I have this :
>
> def recursive_count(target, nested_num_list):
>     """
>       >>> recursive_count(2, [2, 9, [2, 1, 13, 2], 8, [2, 6]])
>       4
>       >>> recursive_count(7, [[9, [7, 1, 13, 2], 8], [7, 6]])
>       2
>       >>> recursive_count(15, [[9, [7, 1, 13, 2], 8], [2, 6]])
>       0
>       >>> recursive_count(5, [[5, [5, [1, 5], 5], 5], [5, 6]])
>       6
>     """
>     for element in nested_num_list:
>         if type(element) == type([]):
>            test = recursive_count(target, element)
>         print element, target
>         if element == target :
>            count = count + 1
>     return count
>
> if __name__ == "__main__":
>     import doctest
>     doctest.testmod()
>
>
> Now I get this message :
>
> UnboundLocalError: local variable 'count' referenced before assignment
>
>
> It is because you are doing count = count + 1
> But where is count defined.
>
>
>
> But if I do this :
>
> def recursive_count(target, nested_num_list):
>     """
>       >>> recursive_count(2, [2, 9, [2, 1, 13, 2], 8, [2, 6]])
>       4
>       >>> recursive_count(7, [[9, [7, 1, 13, 2], 8], [7, 6]])
>       2
>       >>> recursive_count(15, [[9, [7, 1, 13, 2], 8], [2, 6]])
>       0
>       >>> recursive_count(5, [[5, [5, [1, 5], 5], 5], [5, 6]])
>       6
>     """
>   count = 0
>   for element in nested_num_list:
>         if type(element) == type([]):
>            test = recursive_count(target, element)
>         print element, target
>         if element == target :
>            count = count + 1
>     return count
>
> if __name__ == "__main__":
>     import doctest
>     doctest.testmod()
>
> The count will always be 0 if a nested list is being found.
>
> What's the python way to solve this
>
>
> I am not sure what do you want to achieve by this ?
> What is the problem statement ?
>
> The problem statement is that I must count how many times the target is in
> the nested_list.
> So I thougt that every nested list the function is called again so this
> list is also iterated.
>

Let's say n, l = 2, [2, 9, [2, 1, 13, 2], 8, [2, 6]]
Simply Flatten the list l, which will be then be; flatten(l) = [ 2, [2, 9,
2, 1,13, 2, 8, 2, 6 ]
Now count for n; flatten.count(n)

--
~l0nwlf
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