[Tutor] FW: wierd replace problem

[Roelof Wobben]

Oke, 
 
Can this also be the same problem.
 
In the text is this :
 
'tis is represent as  "'this
 
And this
 
part is represent as part.
 
 
Roelof


________________________________
> Date: Tue, 14 Sep 2010 11:41:28 +0100
> From: wprins at gmail.com
> To: tutor at python.org
> Subject: Re: [Tutor] FW: wierd replace problem
>
>
>
> On 14 September 2010 11:09, James Mills
>>
> wrote:
> $ python
> Python 2.6.5 (r265:79063, Jun 13 2010, 14:03:16)
> [GCC 4.4.4 (CRUX)] on linux2
> Type "help", "copyright", "credits" or "license" for more information.
>>>> s = "foo\"bar'"
>>>> s
> 'foo"bar\''
>
> I'd like to point something out here. Typing "s" as James showed here
> at the prompt outputs a version of the string that Python will
> understand if fed again, consequently it's encoded to do the same
> escaping of characters as you would have to do if you put that
> expression into your python source yourself. If however you entered:
>
> print s
>
> ... then Python would've print the value of s as it really is, withou
> any escape characters or anything else, e.g.:
>
>>>> print s
> foo"bar'
>
> So, even though you see a \' in the output posted by James above, the \
> that was output by Python isn't actually part of the string (e.g. it's
> not really there as such), it was only output that way by Python to
> disambiguate the value of the string.
>
> So, at the risk of belaboring this point to death, if you do:
>
> s = '\'\'\''
>
> then the contents of the string s in memory is '''
>
> The string does not contain the slashes. The slashes are only there to
> help you make Python understand that the quotes must not be interpreted
> as the end of the string, but rather as part of the string. You could
> get the exact same result by doing:
>
> s = "'''"
>
> Here there's no ambiguity and consequently no need for slashes since
> the string is delineated by double quotes and not single quotes.
>
> Hope that helps.
>
> Walter
>
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