[Tutor] if value in list of dictionaries

[Norman Khine]

thanks for the reply. i should have been more specific in my question ;)

the order in which 'other' is listed is not always the last item of
the list as it is dependent on where in the CSV file it is included.

what i was trying to do is to take create the list of dictionary items
and then find the item which has name=='other' and then put this as
the last item in the list.

so from this list http://pastie.org/1185974 how do i select the item
name == 'other' and put it at the end of the list?

On Mon, Sep 27, 2010 at 11:39 PM, Emile van Sebille <emile at fenx.com> wrote:
> On 9/27/2010 1:22 PM Norman Khine said...
>
>> what is the correct way to ensure that {'industry': 'travel', 'name':
>> 'other','value': MSG(u"Other")} is always added to the end of this
>> list after all the items have been sorted?
>>
>> here is the code which returns this list:
>
>   options.sort(key=itemgetter('name'))
>   return options
>
> So, to answer the question you ask above, you can do:
>
>   options.sort(key=itemgetter('name'))
>   options.append({'industry':'travel',
>      'name':'other','value':MSG(u"Other")}
>   return options
>
> But I don't think that's the question you're looking to get answered.
>
> I think you want "other" to be found only at the end and not elsewhere.
>
> Then you might try excluding other from options allowing the above to append
> it to the end:
>
> for index, row in enumerate(topics.get_rows()):
>    if row[0] != 'other':
>        options.append({'name': row[0], 'value': MSG(row[1])})
>
> HTH,
>
> Emile
>
>
>
> _______________________________________________
> Tutor maillist  -  Tutor at python.org
> To unsubscribe or change subscription options:
> http://mail.python.org/mailman/listinfo/tutor
>



-- 
˙uʍop ǝpısdn p,uɹnʇ pןɹoʍ ǝɥʇ ǝǝs noʎ 'ʇuǝɯɐן sǝɯıʇ ǝɥʇ puɐ 'ʇuǝʇuoɔ
ǝq s,ʇǝן ʇǝʎ
%>>> "".join( [ {'*':'@','^':'.'}.get(c,None) or
chr(97+(ord(c)-83)%26) for c in ",adym,*)&uzq^zqf" ] )