questions.anon at gmail.com
Tue Aug 9 01:40:40 CEST 2011
Thank you and I will look into shutils, below is the code that did work:
for (path, dirs, files) in os.walk(MainFolder):
for dir in dirs:
for gzfiles in files:
print "dealing with gzfiles:", gzfiles
print "end of processing"
On Mon, Aug 8, 2011 at 6:34 PM, Stefan Behnel <stefan_ml at behnel.de> wrote:
> questions anon, 08.08.2011 01:57:
> Thank you, I didn't realise that was all I needed.
>> Moving on to the next problem:
>> I would like to loop through a number of directories and decompress each
>> *.gz file and leave them in the same folder but the code I have written
>> seems to focus on the last folder. Not sure where I have gone wrong.
>> Any feedback will be greatly appreciated.
>> import gzip
>> import os
>> for (path, dirs, files) in os.walk(MainFolder):
>> for dir in dirs:
>> print "the path and dirs are:", outputfolder
>> for gzfiles in files:
>> print gzfiles
>> if gzfiles[-3:]=='.gz':
>> print 'dealing with gzfiles:', dir, gzfiles
>> print f_in
>> compresseddata=gzip.GzipFile(**f_in, "rb")
>> f_out=open(f_in[:-3], "wb")
> Note how "outputfolder" is set and reset in the first inner loop, *before*
> starting the second inner loop. Instead, build the output directory name
> once, without looping over the directories (which, as far as I understand
> your intention, you can ignore completely).
> Also, see the shutils module. It has a method that efficiently copies data
> between open file(-like) objects. With that, you can avoid reading the whole
> file into memory.
> Tutor maillist - Tutor at python.org
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