[Tutor] List methods inside a dictionary of list

[Rafael Turner]

Hello,

I am playing lists and dictionaries and I came across this
counter-intuitive result.

>>> d = dict(zip(['a', 'q', 'c', 'b', 'e', 'd', 'g', 'j'],8*[[0]]))
>>>d
Out:
{'a': [0],
 'b': [0],
 'c': [0],
 'd': [0],
 'e': [0],
 'g': [0],
 'j': [0],
 'q': [0]}

>>> d['a'].__setitem__(0,4)
>>> d
Out:
{'a': [4],
 'b': [4],
 'c': [4],
 'd': [4],
 'e': [4],
 'g': [4],
 'j': [4],
 'q': [4]}

I was not expecting all the keys to be updated. Is there any
documentation I could read on how different datatypes' methods and
operators interact differently when inside a dictionary?  I would also
like to find a way of being able to use list methods in side a
dictionary so that

>>> d['a'][0] = 5

Does not return

{'a': [5],
 'b': [5],
 'c': [5],
 'd': [5],
 'e': [5],
 'g': [5],
 'j': [5],
 'q': [5]}

But rather

{'a': [5],
 'b': [0],
 'c': [0],
 'd': [0],
 'e': [0],
 'g': [0],
 'j': [0],
 'q': [0]}

Where d is made by d = dict(zip(['a', 'q', 'c', 'b', 'e', 'd', 'g',
'j'],8*[[0]]))

Thanks a bunch,
Rafael