[Tutor] Homework problem

[Ken Baclig]

Does this look right?  Still a little confused....

        if char.isdigit():
           num = int(char) + 1
           a_string[index] = str(num)
print a_string




________________________________
From: Marc Tompkins <marc.tompkins at gmail.com>
To: Ken Baclig <kbaclig at yahoo.com>
Cc: "tutor at python.org" <tutor at python.org>
Sent: Wednesday, July 20, 2011 3:45 PM
Subject: Re: [Tutor] Homework problem


On Wed, Jul 20, 2011 at 2:54 PM, Ken Baclig <kbaclig at yahoo.com> wrote:

Hi,
>
>
>I'm trying to make a function that receives text (a string) as an argument and returns the same text (as string), but with 1 added to each word that is a number.
>
>
>I need help getting started.
>
>
>So far, I have:
>
>
>def FindNumbers(a_string):
>
>
>    for index, char in enumerate(a_string):
>        if char.isdigit():
>a_string[index] = 
>
>
>
>
>def Test():
>
>
>    sometext = "I got 432 when I counted, but Jim got 433 which is a lot foronly 6 cats, or were there 12 cats?"
>    
>    FindNumbers(sometext)
>
>
>Test()
First of all, don't enumerate() the string; split() it instead - this will give you a list of words instead of characters.
Then, look at each item in that list; check to see whether it's numeric - isdigit() works for this.
If it _is_ numeric, convert it to an int, add one to it, and turn it back into a string.
Join the list back into a string, and you're done.

Note: you can step through the items in a list by saying (for example) "for word in words:" - but if you do it that way you can't modify any of the items.  If you need to modify them - by adding 1, for example - you need to refer to them by index instead, and the quickest way to do that is "for x in range(len(words)):  print words[x]".

That was a bunch of broad hints - if you need help putting them together, feel free to ask. 
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