[Tutor] How to replace the '\'s in a path with '/'s?

[Richard D. Moores]

On Sun, Jul 31, 2011 at 03:34, Peter Otten <__peter__ at web.de> wrote:
>
> Sandip Bhattacharya wrote:
>
> > On Sat, Jul 30, 2011 at 10:28:11PM -0700, Richard D. Moores wrote:
> >> File "c:\P32Working\untitled-5.py", line 2
> >>    return path.replace('\', '/')
> >>                                ^
> >> SyntaxError: EOL while scanning string literal
> >> Process terminated with an exit code of 1
> >
> > The first backslash up there is escaping the ending quote. This is  what
> > you want:
> >     return path.replace('\\', '/')
> >
> > Generally, converting slashes manually should be kept at a minimum. You
> > should be using library functions as much as possible. The experts here
> > can correct me here, but this is a roundabout way I would be doing this:
> >
> >     # I use a linux machine. Using this to work with Windows paths
> >     # Use os.path if you are on windows
> >     import ntpath
> >
> >     # Use raw strings so that backslash doesnt matter
> >     path=r'C:\Users\Dick\Desktop\Documents\Notes\College Notes.rtf'
> >
> >     #take out drive first because ntpath.split end sentinel is predictable
> >     #that way
> >     drive,rest = ntpath.splitdrive(path)
> >
> >     # This will store the path components
> >     comps = []
> >     comps.append(drive)
> >
> >     while rest != '\\':
> >         parts = ntpath.split(rest)
> >         comps.insert(1,parts[1])
> >         rest = parts[0]
> >
> >
> >     print '/'.join(comps)
> >
> > I am not happy with the loop to collect the components. But I couldn't
> > find a single path function which splits a path into all the components
> > in one go.
>
> What happens if the path looks like
>
> r"C:relative\path\to\my\file.txt"
>
> or
>
> r"C:/mixed\slashes.txt"?
>
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