[Tutor] Parsing an XML document using ElementTree
Sithembewena Lloyd Dube
zebra05 at gmail.com
Fri Jun 10 16:59:52 CEST 2011
Hi Stefan,
Thanks for the code review :) Only just noticed this.
On Wed, May 25, 2011 at 3:10 PM, Stefan Behnel <stefan_ml at behnel.de> wrote:
> Sithembewena Lloyd Dube, 25.05.2011 14:40:
>
> Thanks for all your suggestions. I read up on gzip and urllib and also
>> learned in the process that I could use urllib2 as its the latest form of
>> that library.
>>
>> Herewith my solution: I don't know how elegant it is, but it works just
>> fine.
>>
>> def get_contests():
>> url = '
>>
>> http://xml.matchbook.com/xmlfeed/feed?sport-id=&vendor=TEST&sport-name=&short-name=Po
>> '
>> req = urllib2.Request(url)
>> req.add_header('accept-encoding','gzip/deflate')
>> opener = urllib2.build_opener()
>> response = opener.open(req)
>>
>
> This is ok.
>
>
>
> compressed_data = response.read()
>> compressed_stream = StringIO.StringIO(compressed_data)
>> gzipper = gzip.GzipFile(fileobj=compressed_stream)
>> data = gzipper.read()
>>
>
> This should be simplifiable to
>
> uncompressed_stream = gzip.GzipFile(fileobj=response)
>
>
>
> current_path = os.path.realpath(MEDIA_ROOT + '/xml-files/d.xml')
>> data_file = open(current_path, 'w')
>> data_file.write(data)
>> data_file.close()
>> xml_data = ET.parse(open(current_path, 'r'))
>>
>
> And this subsequently becomes
>
> xml_data = ET.parse(uncompressed_stream)
>
>
>
> contest_list = []
>> for contest_parent_node in xml_data.getiterator('contest'):
>>
>
> Take a look at ET.iterparse().
>
>
>
> contest = Contest()
>> for contest_child_node in contest_parent_node:
>> if (contest_child_node.tag == "name" and
>> contest_child_node.text is not None and contest_child_node.text != ""):
>> contest.name = contest_child_node.text
>> if (contest_child_node.tag == "league" and
>> contest_child_node.text is not None and contest_child_node.text != ""):
>> contest.league = contest_child_node.text
>> if (contest_child_node.tag == "acro" and
>> contest_child_node.text is not None and contest_child_node.text != ""):
>> contest.acro = contest_child_node.text
>> if (contest_child_node.tag == "time" and
>> contest_child_node.text is not None and contest_child_node.text != ""):
>> contest.time = contest_child_node.text
>> if (contest_child_node.tag == "home" and
>> contest_child_node.text is not None and contest_child_node.text != ""):
>> contest.home = contest_child_node.text
>> if (contest_child_node.tag == "away" and
>> contest_child_node.text is not None and contest_child_node.text != ""):
>> contest.away = contest_child_node.text
>>
>
> This is screaming for a simplification, such as
>
> for child in contest_parent_node:
> if child.tag in ('name', 'league', ...): # etc.
> if child.text:
> setattr(context, child.tag, child.text)
>
>
>
> Stefan
>
> _______________________________________________
> Tutor maillist - Tutor at python.org
> To unsubscribe or change subscription options:
> http://mail.python.org/mailman/listinfo/tutor
>
--
Regards,
Sithembewena Lloyd Dube
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://mail.python.org/pipermail/tutor/attachments/20110610/e53ab61c/attachment.html>
More information about the Tutor
mailing list