[Tutor] Dynamically assign variable names to tuple objects
scarolan at gmail.com
Tue Mar 1 20:49:29 CET 2011
> My advice would be to go read up on the zip() function and the
> str.join() function. Then, if you are using python 2.x, go find
> itertools.izip. It does the same thing as zip but it's more memory
> efficient. With those two you can do it in about two lines or so (and
> maybe a few for set up and clarity and such).
This is what I've got so far:
myfiles = sys.argv[1:]
for i in zip(open(myfiles), open(myfiles), open(myfiles)):
print " ".join(i)
How would you:
1. zip an arbitrary number of files in this manner? I hard-coded it
to do only three.
2. Strip out trailing spaces and line breaks from the lines in each file?
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