[Tutor] Help with python-gnupg
smokefloat at gmail.com
Sat Mar 12 07:55:10 CET 2011
On Sat, Mar 12, 2011 at 1:39 AM, Becky Mcquilling
<ladymcse2000 at gmail.com> wrote:
> If anyone is familiar with python-gnupg, I am having some difficulty with
> the syntax. I've tried the following:
> f = open('c:/test/filename.txt', 'r')
> datae = gpg.encrypt_file(f.read(), 'ladymcse at gmail.com',
> output=open('c:/gpg_test/data.gpg2', 'w'))
> file_to_encrypt = open('c:/gpg_test/data.gpg2', 'w')
> datae = gpg(f.read(), 'ladymcse at gmail.com', output=file_to_encrypt)
> Either way, I can't get the output written to a file, it gives me an error:
> Traceback (most recent call last):
> File "<pyshell#65>", line 1, in <module>
> datae = gpg.encrypt_file(f.read(), 'beckymcq at google.com',
> output=open('c:/test/data.gpg2', 'w'))
> File "C:\Python27\lib\site-packages\gnupg.py", line 583, in encrypt_file
> if os.path.exists(output):
> File "C:\Python27\lib\genericpath.py", line 18, in exists
> TypeError: coercing to Unicode: need string or buffer, file found
This seems to say it needs a string or buffer, but a file was found.
Which says to me, you need to convert the file that is found to a
string before passing it as a parameter to a function. It might be
that output needs to be a string before it is used, so read the file
and string it. It's just a guess from what I see though.
> Any thoughts? Would reallly appreciate the help.
> If you aren't familiar with this and know of resources, it would be awesome.
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