[Tutor] create an xls file using data from a txt file

[Walter Prins]

On 11 May 2011 03:57, tax botsis <taxbotsis at gmail.com> wrote:

> I tried to work that out with xlwt but couldn't. Actually, I started
> working on the following script but I couldn't even split the line for
> further processing:
>
>
OK, I've thrown together a quick sample demonstrating all the concepts you
need (obviously you need to take from this what is relevant to you):

import csv
import xlwt
import os
import sys

# Look for input file in same location as script file:
inputfilename = os.path.join(os.path.dirname(sys.argv[0]),
'tabdelimited.txt')
# Strip off the path
basefilename = os.path.basename(inputfilename)
# Strip off the extension
basefilename_noext = os.path.splitext(basefilename)[0]
# Get the path of the input file as the target output path
targetoutputpath = os.path.dirname(inputfilename)
# Generate the output filename
outputfilename =  os.path.join(targetoutputpath, basefilename_noext+'.xls')

# Create a workbook object
workbook = xlwt.Workbook()
# Add a sheet object
worksheet = workbook.add_sheet(basefilename_noext, cell_overwrite_ok=True)

# Get a CSV reader object set up for reading the input file with tab
delimiters
datareader = csv.reader(open(inputfilename, 'rb'),
                        delimiter='\t', quotechar='"')

# Process the file and output to Excel sheet
for rowno, row in enumerate(datareader):
    for colno, colitem in enumerate(row):
        worksheet.write(rowno, colno, colitem)

# Write the output file.
workbook.save(outputfilename)

# Open it via the operating system (will only work on Windows)
# On Linux/Unix you would use subprocess.Popen(['xdg-open', filename])
os.startfile(outputfilename)


The code is also available at the following URL in case the formatting gets
eaten by the mail system: http://pastebin.com/APpM7EPf

Regards

Walter
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