[Tutor] Python Hard_way 40

[Prasad, Ramit]

>>This stores a reference to the function. The following line is the call to the function.

Just to expand. In Python, you can pass functions like you would anything else. So, the first line before stores the function reference find_city inside the dictionary cities with the key '_find'.  It then looks up the value for the key '_find' which returns a function and then calls the returned function with the arguments cities and state.


cities['_find'] = find_city
city_found = cities['_find'](cities,state)

The previous line is equivalent to
function_name = cities['_find'] # function_name is the equivalent of find_city now
city_found = function_name(cities, state)

And that is equivalent to:
city_found = find_city(cities, state)


Hope that helps,
Ramit



Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
712 Main Street | Houston, TX 77002
work phone: 713 - 216 - 5423

From: tutor-bounces+ramit.prasad=jpmchase.com at python.org [mailto:tutor-bounces+ramit.prasad=jpmchase.com at python.org] On Behalf Of bob gailer
Sent: Wednesday, May 11, 2011 10:39 AM
To: Robert .
Cc: Tutor at python.org
Subject: Re: [Tutor] Python Hard_way 40

On 5/11/2011 11:24 AM, Robert . wrote:
Hi all,

My first post ever! :)
I'm following the guide "Learn Python the Hard Way" and have reached a point where I am struggling to understand the code and unfortunately the authors guide hasn't cleared it up for me. (excercise 40 for reference)

The main confusion is coming from 'cities['_find'] = find_city' I'm not sure what this is really doing.

>From my learning, this should add an extra item to the dict with the index name of "_find" and the value which is returned from "find_city" function.

This stores a reference to the function. The following line is the call to the function.

city_found = cities['_find'](cities,state)

[snip]


--

Bob Gailer

919-636-4239

Chapel Hill NC


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