[Tutor] a quick Q: how to use for loop to read a series of files with .doc end

[lina]

On Fri, Oct 7, 2011 at 9:38 AM, Dave Angel <d at davea.name> wrote:

> On 10/06/2011 12:21 PM, lina wrote:
>
>> <snip>
>>
>>
>>> As for splitting into functions, consider:
>>>
>>> #these two are capitalized because they're intended to be constant
>>> TOKENS = "BE"
>>> LINESTOSKIP = 43
>>> INFILEEXT = ".xpm"
>>> OUTFILEEXT = ".txt"
>>>
>>> def dofiles(topdirectory):
>>>    for filename in os.listdr(topdirectory):
>>>        processfile(filename)
>>>
>>> def processfile(infilename):
>>>    base, ext =os.path.splitext(fileName)
>>>    if ext == INFILEEXT:
>>>        text = fetchonefiledata(infilename)
>>>        numcolumns = len(text[0])
>>>        results = {}
>>>        for ch in TOKENS:
>>>
>>>            results[ch] = [0] * numcolumns
>>>        for line in text:
>>>            line = line.strip()
>>>
>>>            for col, ch in enumerate(line):
>>>                if ch in tokens:
>>>                    results[ch][col] += 1
>>>
>>>  I still have trouble understanding the results[ch][col] part.
>>
>> Thanks ahead,
>>
>>
>>  First ask yourself what results consists of.  It's a dictionary, which is
> a aggregate of pairs of key/value items.  In each case the key is a
> character, and the the value is a list of numbers.
>
> So results[ch] is a particular value, in other words a list.
>
> And results[ch] [col] is a particular item of the list, in other words, and
> integer
>
> If we use += 1 on that integer, we increment it by 1
>
> Is that clear?   if not, write a separate program to build such as
> structure, and try printing out each level of item
>     print results["E"]
> should display a list
>      print results["E"][0]
> should display an integer
>      print results["E"][1]
>      print results["E"][2]
>

Yes. I understand this part now. But how can I print a list consists of the
value of key B + E.

For {'B': [4, 5, 6], 'E': [1, 2, 3]}

I wanna get the summary of B and E in each column, namely [5, 7, 9]


>
>
> Does this help?
>
> --
>
> DaveA
>
>


-- 
Best Regards,

lina
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