[Tutor] Pyinstaller Database
George Nyoro
geonyoro at gmail.com
Thu Oct 13 21:54:41 CEST 2011
Hi guys:
Im a beginner in coding and wanted to distribute some of my code to
friends on linux distros. Pyinstaller works well enough. Theres a
situation where I use pickle module to save data to an external file.
The file is not a py file and when I use pyinstaller, it does nt
compile the file too. Is there anyway I can make a none *.py file or
use a databse file s that it is compiled too?
On 13/10/2011, tutor-request at python.org <tutor-request at python.org> wrote:
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> Today's Topics:
>
> 1. Re: problem with using set (delegbede at dudupay.com)
> 2. Re: map one file and print it out following the sequence
> (Dave Angel)
> 3. Re: problem with using set (Dave Angel)
> 4. Re: problem with using set (Prasad, Ramit)
>
>
> ----------------------------------------------------------------------
>
> Message: 1
> Date: Thu, 13 Oct 2011 15:18:24 +0000
> From: delegbede at dudupay.com
> To: "tutor at python.org" <tutor at python.org>
> Subject: Re: [Tutor] problem with using set
> Message-ID:
> <263695032-1318519103-cardhu_decombobulator_blackberry.rim.net-1700908878- at b18.c12.bise7.blackberry>
>
> Content-Type: text/plain
>
> +1 Ramit.
> Sent from my BlackBerry wireless device from MTN
>
> -----Original Message-----
> From: "Prasad, Ramit" <ramit.prasad at jpmorgan.com>
> Sender: tutor-bounces+delegbede=dudupay.com at python.org
> Date: Thu, 13 Oct 2011 11:09:24
> To: tutor at python.org<tutor at python.org>
> Subject: Re: [Tutor] problem with using set
>
> Approach:-
>>>> a='hello'
>>>> set(a)
> set(['h', 'e', 'l', 'o']), so i am thinking somehow if i remove 'l' and i
> join the string, i will get the desired output.
>
> 2.
>>>> a='microsoft'
>>>> set(a)
> set(['c', 'f', 'i', 'm', 'o', 's', 'r', 't'])
>>>> print ''.join(set(a))
> cfimosrt
>
> When i print "Hello", i get the output as "helo"(in same sequence) but when
> i write "microsoft" i get this-"cfimosrt". So, it means i can't predict the
> outcome of set(a)??
> =========================================================================
>
> Are you required to use set? If you are not, I think the following will be
> easier.
>>>> 'hello'.replace( 'l', '' )
> 'heo'
>>>> 'microsoft'.replace( 'o', '' )
> 'micrsft'
>
> If you require set, you can do:
>
>>>> s = set("microsoft")
>>>> s
> set(['c', 'f', 'i', 'm', 'o', 's', 'r', 't'])
>>>> s.remove('o')
>>>> string = []
>>>> for letter in 'microsoft':
> ... if letter in s:
> ... string.append( letter )
> ...
>>>> ''.join( string )
> 'micrsft'
>
>
> Ramit
>
>
> Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
> 712 Main Street | Houston, TX 77002
> work phone: 713 - 216 - 5423
>
>
>
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> ------------------------------
>
> Message: 2
> Date: Thu, 13 Oct 2011 11:43:15 -0400
> From: Dave Angel <d at davea.name>
> To: lina <lina.lastname at gmail.com>
> Cc: tutor at python.org
> Subject: Re: [Tutor] map one file and print it out following the
> sequence
> Message-ID: <4E970713.6020001 at davea.name>
> Content-Type: text/plain; charset=ISO-8859-1; format=flowed
>
> On 10/13/2011 09:09 AM, lina wrote:
>> <snip>
>>
>>> I think your final version of sortfile() might look something like:
>>>
>>> def sortfile(infilename=**INFILENAME, outfilename=OUTFILENAME):
>>> infile = open(infilename, "r")
>>> intext = infile.readlines()
>>> outfile = open(OUTFILENAME, "w")
>>> for chainid in CHAINID:
>>> print("chain id = ",chainid)
>>> sortoneblock(chainid, intext, outfile)
>>> infile.close()
>>> outfile.close()
>>>
>>
>> $ python3 map-to-itp.py
>> {'O4': '2', 'C19': '3', 'C21': '1'}
>> C
>> Traceback (most recent call last):
>> File "map-to-itp.py", line 55, in<module>
>> sortfile()
>> File "map-to-itp.py", line 17, in sortfile
>> sortoneblock(chainid,intext,OUTFILENAME)
>> File "map-to-itp.py", line 29, in sortoneblock
>> f.write(line[1].strip() for line in temp)
>> TypeError: must be str, not generator
>>
>>
>
> When you see an error message that describes a generator, it means you
> usually have a for-expression used as a value.
>
> At your stage of learning you probably be ignoring generators and list
> comprehensions, and just write simple for loops. So you should replace
> the f.write with a loop.
>
>
> for item in temp:
> f.write(something + "\n")
>
> One advantage is that you can easily stuff print() functions into the
> loop, to debug what's really happening. After you're sure it's right,
> it might be appropriate to use either a generator or a list comprehension.
>
>> I don't know how to fix the writing issue.
>>
>> can I write the different chainID one into the same OUTFILE?
>>
>> Thanks, I attached the code I used below:
>>
>> #!/usr/bin/python3
>>
>> import os.path
>>
>> LINESTOSKIP=0
>> CHAINID="CDEFGHI"
>> INFILENAME="pdbone.pdb"
>> OUTFILENAME="sortedone.pdb"
>> DICTIONARYFILE="itpone.itp"
>> mapping={}
>> valuefromdict={}
>>
>> def sortfile():
>> intext=fetchonefiledata(INFILENAME)
>> for chainid in CHAINID:
>> print(chainid)
>> sortoneblock(chainid,intext,OUTFILENAME)
>>
> One way to get all the output into one file is to create the file in
> sortfile(), and pass the file object. Look again at what I suggested
> for sortfile(). If you can open the file once, here, you won't have the
> overhead of constantly opening the same file that nobody closed, and
> you'll have the side benefit that the old contents of the file will be
> overwritten.
>
> Andreas' suggestion of using append would make more sense if you wanted
> the output to accumulate over multiple runs of the program. If you
> don't want the output file to be the history of all the runs, then
> you'll need to do one open(name, "w"), probably in sortfile(), and then
> you might as well pass the file object as I suggested.
>
>
>>
>>
>> def sortoneblock(cID,TEXT,OUTFILE):
>
> If you followed my suggestions for sortfile(), then the last paramter to
> this function would be outfile., and you could use outfile.write().
> As Andreas says, don't use uppercase for non-constants.
>
>> temp = []
>
> #this writes the cID to the output file, once per cID
> outfile.write(cID + "\n")
>
>> for line in TEXT:
>> blocks=line.strip().split()
>> if len(blocks)== 11 and blocks[3] == "CUR" and blocks[4] == cID
>> and
>> blocks[2] in mapping.keys():
>
> if (len(blocks)== 11 and blocks[3] == "CUR"
> and blocks[4] == cID and blocks[2] in mapping ):
>
> Having the .keys() in that test is redundant and slows execution down
> quite a bit. "in" already knows how to look things up efficiently in a
> dictionary, so there's no use in converting to a slow list before doing
> the slow lookup.
> Also, if you put parentheses around the whole if clause, you can span it
> across multiple lines without doing anything special.
>
>
>> temp.append((mapping[blocks[2]],line))
>> temp.sort()
>> with open(OUTFILE,"w") as f:
>> f.write(line[1].strip() for line in temp)
>>
> See comment above for splitting this write into a loop. You also are
> going to have to decide what to write, as you have tuple containing both
> an index number and a string in each item of temp. Probably you want to
> write the second item of the tuple. Combining these changes, you
> would have
> for index, line in temp:
> outfile.write(line + "\n")
>
> Note that the following are equivalent:
> for item in temp:
> index, line = item
> outfile.write(line + "\n")
>
> for item in temp:
> outfile.write(item[1] + "\n")
>
> But I like the first form, since it makes it clear what's been stored in
> temp. That sort of thing is important if you ever change it.
>>
>>
>>
>> def generatedictionary(dictfilename):
>> text=fetchonefiledata(DICTIONARYFILE)
>> for line in text:
>> parts=line.strip().split()
>> if len(parts)==8:
>> mapping[parts[4]]=parts[0]
>> print(mapping)
>>
>>
>>
>> def fetchonefiledata(infilename):
>> text=open(infilename).readlines()
>> if os.path.splitext(infilename)[1]==".itp":
>> return text
>> if os.path.splitext(infilename)[1]==".pdb":
>> return text[LINESTOSKIP:]
>> infilename.close()
>>
>>
>> if __name__=="__main__":
>> generatedictionary(DICTIONARYFILE)
>> sortfile()
>>
>
> Final note: write() doesn't automatically append a newline, so I tend to
> add an explicit one in the write() itself. But if you start seeing
> double spacing, that's presumably because the line already had a newline
> in it. You could use rstrip() on it (my choice), or remove the + "\n"
> in the write() method.
>
> --
>
> DaveA
>
>
> ------------------------------
>
> Message: 3
> Date: Thu, 13 Oct 2011 12:43:54 -0400
> From: Dave Angel <d at davea.name>
> To: Praveen Singh <c2praveen30jun at gmail.com>
> Cc: tutor at python.org
> Subject: Re: [Tutor] problem with using set
> Message-ID: <4E97154A.2070607 at davea.name>
> Content-Type: text/plain; charset=ISO-8859-1; format=flowed
>
> On 10/13/2011 10:44 AM, Praveen Singh wrote:
>> <SNIP>
>>
>> 2.
>>>>> a='microsoft'
>>>>> set(a)
>> set(['c', 'f', 'i', 'm', 'o', 's', 'r', 't'])
>>>>> print ''.join(set(a))
>> cfimosrt
>>
>> When i print "Hello", i get the output as "helo"(in same sequence) but
>> when
>> i write "microsoft" i get this-"cfimosrt". So, it means i can't predict
>> the
>> outcome of set(a)??
>>
> The set() function converts its input into a set. A set is not ordered
> in the usual way, but in such a way as to rapidly find whether a
> particular item exists already in the set, and insert it if not.
> Inserting a new item might totally rearrange the existing ones, set
> doesn't promise anything at all about the order. (Dictionaries are
> similar, but while set has only a key, dict has both key and value)
>
> A set has no value to the assignment as stated. Stick to lists.
>
>
> --
>
> DaveA
>
>
>
> ------------------------------
>
> Message: 4
> Date: Thu, 13 Oct 2011 13:31:53 -0400
> From: "Prasad, Ramit" <ramit.prasad at jpmorgan.com>
> To: "tutor at python.org" <tutor at python.org>
> Subject: Re: [Tutor] problem with using set
> Message-ID:
> <0604E20B5F6F2F4784C9C8C71C5DD4DD2F2165E19A at EMARC112VS01.exchad.jpmchase.net>
>
> Content-Type: text/plain; charset="us-ascii"
>
> ----Original Message-----
> From: tutor-bounces+ramit.prasad=jpmorgan.com at python.org
> [mailto:tutor-bounces+ramit.prasad=jpmorgan.com at python.org] On Behalf Of
> Prasad, Ramit
> Sent: Thursday, October 13, 2011 10:09 AM
> To: tutor at python.org
> Subject: Re: [Tutor] problem with using set
>
> Approach:-
>>>> a='hello'
>>>> set(a)
> set(['h', 'e', 'l', 'o']), so i am thinking somehow if i remove 'l' and i
> join the string, i will get the desired output.
>
> 2.
>>>> a='microsoft'
>>>> set(a)
> set(['c', 'f', 'i', 'm', 'o', 's', 'r', 't'])
>>>> print ''.join(set(a))
> cfimosrt
>
> When i print "Hello", i get the output as "helo"(in same sequence) but when
> i write "microsoft" i get this-"cfimosrt". So, it means i can't predict the
> outcome of set(a)??
> =========================================================================
>
> Are you required to use set? If you are not, I think the following will be
> easier.
>>>> 'hello'.replace( 'l', '' )
> 'heo'
>>>> 'microsoft'.replace( 'o', '' )
> 'micrsft'
>
> If you require set, you can do:
>
>>>> s = set("microsoft")
>>>> s
> set(['c', 'f', 'i', 'm', 'o', 's', 'r', 't'])
>>>> s.remove('o')
>>>> string = []
>>>> for letter in 'microsoft':
> ... if letter in s:
> ... string.append( letter )
> ...
>>>> ''.join( string )
> 'micrsft'
> ==============================================
> After further thought, I think you might want to keep one of each character
> and not remove them all. If so, see below.
>
>
>>>> string = 'microsoft'
>>>> dct = {}
>>>> for letter in string:
> ... dct[ letter ] = string.count( letter )
> ...
>>>> for letter, count in dct.iteritems():
> ... reversed_string = string[::-1] # reverse string to leave first
> occurrence
> ... reversed_string = reversed_string.replace( letter, '', count-1 )
> ... string = reversed_string[::-1] # return it to normal
> ...
>>>> string
> 'microsft'
>
> If you do not care which duplicate character is left you can skip the lines
> with [::-1] and it will leave the last one in the string.
>
>
> Ramit
>
>
> Ramit Prasad | JPMorgan Chase Investment Bank | Currencies Technology
> 712 Main Street | Houston, TX 77002
> work phone: 713 - 216 - 5423
>
>
>
> This email is confidential and subject to important disclaimers and
> conditions including on offers for the purchase or sale of
> securities, accuracy and completeness of information, viruses,
> confidentiality, legal privilege, and legal entity disclaimers,
> available at http://www.jpmorgan.com/pages/disclosures/email.
> _______________________________________________
> Tutor maillist - Tutor at python.org
> To unsubscribe or change subscription options:
> http://mail.python.org/mailman/listinfo/tutor
>
>
> ------------------------------
>
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>
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