# [Tutor] range question

Joel Goldstick joel.goldstick at gmail.com
Thu Sep 22 16:56:05 CEST 2011

```On Thu, Sep 22, 2011 at 10:37 AM, Dave Angel <d at davea.name> wrote:

> **
> On 09/22/2011 10:27 AM, Joel Knoll wrote:
>
> Given a range of integers (1,n), how might I go about printing them in the following patterns:
> 1 2 3 4 ... n2 3 4 5 ... n 13 4 5 6 ... n 1 2
> etc., e.g. for a "magic square". So that for the range (1,5) for example I would get
> 1 2 3 42 3 4 13 4 1 24 1 2 3
> I just cannot figure out how to make the sequence "start over" within a row, i.e. to go from 4 down to 1 in this example.
> I have been grappling with this problem for 2.5 days and have gotten nowhere!
>
>
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>  Seems like the easiest way would be to duplicate the range once (so you
> have a list twice as long), and then use various slices of it.
>
> x = list(range(1, 5))   #could omit the list() function in python 2.x
> x2 = x+x
>
> for the nth row, use
>    row = x2[n:n+n]
>
>
>
> --
>
> DaveA
>
>
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>
I did it like this:

The trick when cycling through numbers is to use the modulo operator (%)
which gives the integer remainder after division

#!/usr/bin/env python

""" Print magic square give range n like so:
If n is 5

1234
2341
3412
4123
"""

n = 5

for row in range(n):
for col in range(n):
print (row + col) % n + 1,
print

--

1 2 3 4 5
2 3 4 5 1
3 4 5 1 2
4 5 1 2 3
5 1 2 3 4

Joel Goldstick
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