[Tutor] 2.7.3 Popen argument issues

[Ray Jones]

Is there a method by which I can get an exact representation of command
line arguments passed by Popen as seen by the called program? The
argument error I receive shows me an argument that looks exactly like
the argument that I use with Bash (it should - I copied and pasted it) -
but the Bash version works while the Python version doesn't.

The purpose is to capture http streaming video to a file and also split
it out to a local port so that I can pop in and monitor where I am in
the stream.

Here is my Bash call to vlc (it works):

vlc http://"$HOST":$PORT -I dummy --sout 
'#duplicate{dst="transcode{vb=400}:std{access=file,mux=avi,dst=testing.avi}",dst="std{access=http,mux=mpjpeg,dst=127.0.0.1:11300}"}'
&

Here is my Python call to vlc (error response to follow):

vlcExec = sp.Popen(['vlc', 'http://' + ip + ':' + port, '-I dummy',
'--sout
\'#duplicate{dst="transcode{vb=400}:std{access=file,mux=avi,dst=outFile
+ '.avi}",dst="std{access=http,mux=mpjpeg,dst=127.0.0.1:11300}"}\''])

(That is not an escaped double quote at the end - that is " \' " and " ' ").

Here is the resulting error from vlc:

vlc: unknown option or missing mandatory argument `--sout
'#duplicate{dst="transcode{vb=400}:std{access=file,mux=avi,dst=testing.avi}",dst="std{access=http,mux=mpjpeg,dst=127.0.0.1:11300}"}''