[Tutor] correct way to encode

[Norman Khine]

hello, i have this code from the google fusion table api:

(zmgc)☺  python
            * master 9e4be39 ✗zmgc"
Python 2.7.2 (default, Jan 28 2012, 14:53:22)
[GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> import csv
>>> import urllib2, urllib
>>> request_url = 'https://www.google.com/fusiontables/api/query'
>>> query = 'SELECT * FROM 3027809'
>>> url = "%s?%s" % (request_url, urllib.urlencode({'sql': query}))
>>> serv_req = urllib2.Request(url=url)
>>> serv_resp = urllib2.urlopen(serv_req)
>>> reader = csv.DictReader(serv_resp)
>>> for row in reader:
...     print row
...
{'Name': 'Portugal', 'Contact': 'info at zeitgeistportugal.org', 'Link':
'http://www.zeitgeistportugal.org/', 'Location': 'Portugal', 'Type':
'Country', 'Icon': '1'}
{'Name': 'Porto', 'Contact': 'porto at zeitgeistportugal.org', 'Link':
'http://porto.zeitgeistportugal.org', 'Location': 'Porto, Portugal',
'Type': 'Region', 'Icon': '2'}
{'Name': 'Lisboa', 'Contact': 'lisboa at zeitgeistportugal.org', 'Link':
'http://lisboa.zeitgeistportugal.org', 'Location': 'Lisbon, Portugal',
'Type': 'Region', 'Icon': '2'}
{'Name': '\xd0\x91\xd1\x8a\xd0\xbb\xd0\xb3\xd0\xb0\xd1\x80\xd0\xb8\xd1\x8f',
'Contact': 'zgeistbg at gmail.com', 'Link':
'http://thezeitgeistmovement.bg/', 'Location': 'Bulgaria', 'Type':
'Country', 'Icon': '1'}


the table has a mix of charecters:
https://www.google.com/fusiontables/DataSource?docid=1epTUiUlv5NQK5x4sgdy1K47ACDTpHH60hbng1qw

what will be the correct way to encode the items in each dictionary row?

thanks

norman

-- 
%>>> "".join( [ {'*':'@','^':'.'}.get(c,None) or
chr(97+(ord(c)-83)%26) for c in ",adym,*)&uzq^zqf" ] )