[Tutor] How to print something just after 3 attempts?

kala Vinay kala586 at gmail.com
Wed Jul 18 07:11:55 CEST 2012


>
> On Tue, Jul 17, 2012 at 11:10 AM, Santosh Kumar <sntshkmr60 at gmail.com>
> wrote:
> > Hello There,
> >
> > This problem isn't so simple as it looks in the title/subject of this
> email.
> >
> > I am doing a tutorial on Python, and there is a script named password.py:
> >
> > password = "foobar"
> >
> > while password != "unicorn":
> >     password = raw_input("Password: ")
> > print "Welcome in"
> >
> >
> > The question says "Modify the password guessing program to keep track
> > of how many times the user has entered the password wrong. If it is
> > more than 3 times, print ?That must have been complicated.?
> >
> > So I did, I did it in two ways.
> > Case I:
> > password = "foobar"
> > attempt = 0
> > while password != "unicorn":
> >     password = raw_input("Password: ")
> >     attempt = attempt + 1
> >     if attempt == 3:
> >         print "That must have been complicated.."
> >
> > print "Welcome in.."
> > # This script does the half of work. This prints that statement after
> > three attempts but lets you enter password more time.
> >
> >
> > Case II:
> > password = "foobar"
> > attempt = 0
> > while password != "unicorn":
> >     password = raw_input("Password: ")
> >     attempt = attempt + 1
> >     if attempt == 3:
> >         print "That must have been complicated.."
> >         break
> > print "Welcome in.."
> move the print "Welcome under break:
>           break
>           print "Welcome..."
>
> > # This script performs better than first one, but the problem is it
> > welcomes you even if you haven't entered the password correct.
> >
> > Please tell, what can I do?
> > _______________________________________________
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>
>
>
> --
> Joel Goldstick
>
>
> ------------------------------
>

    Hello Joel,

                You can also use getpass() method to read the password, it
will not display the entered characters on screen.

import getpass
attempt=0
for attempt in range(3):
    pw=getpass.getpass()
    if pw=="unicorn":
        print "welcome in.. "
        break
else:
    print "That must have been complicated.. "


-- 
Regards,
Kala
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