# [Tutor] Counting Items in a List

mariocatch mariocatch at gmail.com
Wed Jun 20 15:34:21 CEST 2012

```Hello,

Not sure if this is what you're trying to solve, although it sounds like it
I think what you have is more complicated than it needs to be for something
that simple:
Why not something like this?

*    paragraph = """I have been learning Python and trying little bits of
coding for a while. Recently I tried to have a paragraph and create a list
of its words, then counting those words. Here is the code:"""*
*    splitParagraph = paragraph.strip().split(' ')
print len(splitParagraph) # yields 36
print splitParagraph # yields a list [] of each word separated by
split()*

**
-Mario

On Wed, Jun 20, 2012 at 8:53 AM, Oğuzhan Öğreden <ogreden at gmail.com> wrote:

> Hi,
>
> I have been learning Python and trying little bits of coding for a while.
> Recently I tried to have a paragraph and create a list of its words, then
> counting those words. Here is the code:
>
>  import re
>>
>>
>>> a = """Performs the template substitution, returning a new string.
>>> mapping is any dictionary-like \
>>
>> object with keys that match the placeholders in the template.
>>> Alternatively, you can provide keyword \
>>
>> arguments, where the keywords are the placeholders. When both mapping and
>>> kws are given and there \
>>
>> are duplicates, the placeholders from kws take precedence."""
>>
>>
>>> b = []
>>
>> c = 0
>>
>>
>>> for y in a.split(" "):
>>
>> b.append(y.lower())
>>
>>  if  re.search(",", y) != None:
>>
>>  c = b.index(y.lower())
>>
>>  b.remove(y.lower())
>>
>>  b.insert(c, y.strip(",").lower())
>>
>>  b.sort()
>>
>>  b.extend(["you"])
>>
>>  count = 0
>>
>>
>>> for x in b:
>>
>>  count = b.count(x)
>>
>>   if count > 1:
>>
>>  c = b.index(x)
>>
>>  if b[c+1] != x is True:
>>
>>  print "%s listede %d tane var." % (x, count)
>>
>>  else:
>>
>>  print "%s listede %d tane var." % (x, count)
>>
>>
>>>
> And here are the questions:
>
>
>    - This code doesn't print for the items that occur more than one time.
>    Why?
>    - And actually as I was writing, I realized that "if b[c+1]" may
>    return an error if the last item on the list occured more than one,
>    however, it didn't even if a manually made the last item occur two times.
>    Was my initial expectation a false one? If not, how could I turn it into a
>    b[c-1] so that it will not fail in first item?
>
> Thanks,
> Oğuzhan
>
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```