[Tutor] count numbers only in the string

[Joel Goldstick]

On Tue, Mar 6, 2012 at 3:49 PM, Joel Goldstick <joel.goldstick at gmail.com> wrote:
> On Tue, Mar 6, 2012 at 3:07 PM, kumar s <ps_python at yahoo.com> wrote:
>> Hi :
>>
>> I have some strings with both alpha-numeric strings. I want to add all the numbers in that string and leave characters and special characters.
>> 1A0G19
>>
>> 5G0C25^C52
>>
>> 0G2T3T91
>> 44^C70
>>
>> How can I count only the numbers in the above.
>>
>> 1 A 0 G 19       =    1+0+19 = 20
>>
>> 5 G 0 C 25 ^C 52  =   5+0+25+52 = 82
>>
>> 0 G 2 T 3 T 91    =  0+2+3+91 =  96
>> 44 ^C 70   =   44+70 =  114
>>
>>  In first string 1A0G19  I am only adding 1, 0, and 19.    I am not splitting 19 to add 1+9 which will give totally wrong answer for me.
>>
>>
>> Is there a way I can do this.
>>
>> Thanks for your advise.
>>
>> kumar
>>
>> _______________________________________________
>> Tutor maillist  -  Tutor at python.org
>> To unsubscribe or change subscription options:
>> http://mail.python.org/mailman/listinfo/tutor
>
> I am pretty much a novice with regular expressions, but this seems to
> work to find all the numeric sequences:
>
>>>> source = 'ab123t&4533www'
>>>> re.findall('\d*', source)
> ['', '', '123', '', '', '4533', '', '', '', '']
>>>>
> so then something like this:
>
> total = 0
> my_list = re.findall('\d*', source)
> for my_number in my_list:
>    if my_number != ''
>        total += int(my_number)
>
>
>
> --
> Joel Goldstick

Here is a shorter way:

>>> source = 'ab123t&4533www'
>>> my_list = re.findall('\d*', source)
>>> my_list
['', '', '123', '', '', '4533', '', '', '', '']
>>> sum(int(s) for s in my_list if s != '')
4656


-- 
Joel Goldstick