# [Tutor] count numbers only in the string

Joel Goldstick joel.goldstick at gmail.com
Tue Mar 6 22:12:44 CET 2012

On Tue, Mar 6, 2012 at 3:58 PM, Joel Goldstick <joel.goldstick at gmail.com> wrote:
> On Tue, Mar 6, 2012 at 3:49 PM, Joel Goldstick <joel.goldstick at gmail.com> wrote:
>> On Tue, Mar 6, 2012 at 3:07 PM, kumar s <ps_python at yahoo.com> wrote:
>>> Hi :
>>>
>>> I have some strings with both alpha-numeric strings. I want to add all the numbers in that string and leave characters and special characters.
>>> 1A0G19
>>>
>>> 5G0C25^C52
>>>
>>> 0G2T3T91
>>> 44^C70
>>>
>>> How can I count only the numbers in the above.
>>>
>>> 1 A 0 G 19       =    1+0+19 = 20
>>>
>>> 5 G 0 C 25 ^C 52  =   5+0+25+52 = 82
>>>
>>> 0 G 2 T 3 T 91    =  0+2+3+91 =  96
>>> 44 ^C 70   =   44+70 =  114
>>>
>>>  In first string 1A0G19  I am only adding 1, 0, and 19.    I am not splitting 19 to add 1+9 which will give totally wrong answer for me.
>>>
>>>
>>> Is there a way I can do this.
>>>
>>>
>>> kumar
>>>
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>>
>> I am pretty much a novice with regular expressions, but this seems to
>> work to find all the numeric sequences:
>>
>>>>> source = 'ab123t&4533www'
>>>>> re.findall('\d*', source)
>> ['', '', '123', '', '', '4533', '', '', '', '']
>>>>>
>> so then something like this:
>>
>> total = 0
>> my_list = re.findall('\d*', source)
>> for my_number in my_list:
>>    if my_number != ''
>>        total += int(my_number)
>>
>>
>>
>> --
>> Joel Goldstick
>
> Here is a shorter way:
>
>>>> source = 'ab123t&4533www'
>>>> my_list = re.findall('\d*', source)

if you change above to '\d+' it will only pick up the numbers so below
you can do
>>>> sum(int(s) for s in my_list)

which is even simpler.
>>>> my_list
> ['', '', '123', '', '', '4533', '', '', '', '']
>>>> sum(int(s) for s in my_list if s != '')
> 4656
>

Sorry for my messing up the regex in the first try
>
> --
> Joel Goldstick

--
Joel Goldstick