[Tutor] How to exit this loop in the interpreter
alkopop79 at gmail.com
Thu May 3 17:52:31 CEST 2012
I've been struggling to set up python on snow leopard, mac os x. Stupidly I
downloaded and installed python 3.2 and since then the 'python' command in
the terminal yields 'no command found'. In addition when opening the
terminal I get this error message on the top of the window:
For some reason the installation littered my Android SDK folder with
main.py and other kind of python files. Don't ask me why, it's beyond me. I
removed the offending files manually and deleted the python 3.2.2 folder
form /Library/Frameworks/python.framework/versions folder. After rebooting
the terminal still complains about those files. I wonder how can I fix it?
I would love to learn to use python! Your help would be appreciated!
On 3 May 2012 15:22, Simon Yan <simonyan at fedoraproject.org> wrote:
> On Thu, May 3, 2012 at 9:57 PM, <spawgi at gmail.com> wrote:
>> Hello all,
>> I have encountered the following scenario.
>> Here is the code - on IDLE on Windows XP.
>> *>>> while True:
>> number = raw_input("enter number - ")
>> print number * number
>> except ValueError:
>> print "invalid number"
>> print "unspecified exception"
>> print "other conditions"
>> enter number - 3
>> unspecified exception
>> What I noticed is that no matter, what input I give, I cannot exit this
>> loop. I have tried control-C, control-D etc. all the keys. So how can I
>> exit from this loop?
> If you simply want to stop after an exception was caught, you can insert
> "break" after each print line. Like below:
> >>> while True:
> number = raw_input("enter number - ")
> print number * number
> except ValueError:
> print "invalid number"
> print "unspecified exception"
> print "other conditions"
>> Thanks and Regards,
>> We can do it and do it better.
>> Tutor maillist - Tutor at python.org
>> To unsubscribe or change subscription options:
> YeeYaa (Simon Yan)
> Tutor maillist - Tutor at python.org
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