[Tutor] A simple "if" and "elif" problem

[xgermx]

Python novice here. Caveat emptor.

Since all python input is read in as a string, you could try checking
to see if the value is a digit with the .isdigit string method.
e.g.
 if userinput.isdigit():
   #do stuff
else
  #more stuff

http://stackoverflow.com/questions/5424716/python-how-to-check-if-input-is-a-number-given-that-input-always-returns-stri
http://docs.python.org/library/stdtypes.html

On Sat, May 5, 2012 at 1:08 PM, Emile van Sebille <emile at fenx.com> wrote:
> On 5/5/2012 11:01 AM Santosh Kumar said...
>
>> I am reading the documentation and I'm in the section 4.1. Let me
>> write it down here:
>
>
> You'll need to peek ahead to section 8 Errors and Exceptions.
>
> Try and see if that doesn't get you going.
>
> Emile
>
>
>
>
>>
>>>>> x = int(input("Please enter an integer: "))
>>
>> Please enter an integer: 42
>>>>>
>>>>> if x<  0:
>>
>> ...      x = 0
>> ...      print('Negative changed to zero')
>> ... elif x == 0:
>> ...      print('Zero')
>> ... elif x == 1:
>> ...      print('Single')
>> ... else:
>> ...      print('More')
>> ...
>> More
>>
>> Now I want to add a filter in this script, I want when a user enter a
>> string here it give a warning "Please enter a number like 0 or 2".
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>
>
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