[Tutor] rounding up to the nearest multiple of 8

[Steven D'Aprano]

On Thu, Oct 04, 2012 at 05:26:13PM -0400, eryksun wrote:
> On Thu, Oct 4, 2012 at 4:04 PM, Joel Goldstick <joel.goldstick at gmail.com> wrote:
> >
> >>>> my_string = "123"
> >>>> pad = 8 - len(my_string) % 8
> >>>> my_string = my_string + " " * pad
> >>>> my_string
> > '123     '
> 
> If len(my_string) is already a multiple of 8, the above sets pad to 8:
> 
>     >>> s = "12345678"
>     >>> pad = 8 - len(my_string) % 8
>     >>> pad
>     8

Here's another way:


py> from __future__ import division
py> from math import ceil
py> "%*s" % (int(ceil(len(mystring)/8)*8), mystring)
'    123412341234'


Or left-justified:

py> "%-*s" % (int(ceil(len(mystring)/8)*8), mystring)
'123412341234    '


In Python 3, there is no need for the "from __future__" line.



-- 
Steven