# [Tutor] python help!

D.V.N.Sarma డి.వి.ఎన్.శర్మ dvnsarma at gmail.com
Sun Feb 10 02:36:14 CET 2013

```I have altered the program to run on Python 2.7.3
Perhaps it will run on Python 3 with small/or no alterations.

print("=======================")
print("1-binary to denary")
print("2-denary to binary")
print("3-exit")
print("=======================")

while True:

choice = raw_input("please enter an option: ")

if choice == '1':
binary = raw_input("Please enter a binary number: ")
denary = 0
place_value = 1

for i in binary [::-1]:
denary += place_value * int(i)
place_value *= 2

print("The result is",denary)

elif choice == '2':
denary2 = int(raw_input("Please enter a denary number: "))
remainder = ''
if denary2 not in range(0,256):
denary2 = int(input("Please enter a denary number: "))
continue
while denary2 > 0:
remainder = str(denary2 % 2) + remainder
denary2 /= 2
print("The result is",remainder)

elif choice == '3': break

elif choice == '1' or choice == '2' or choice == '3':
print("Invalid input-try again!")

On Sun, Feb 10, 2013 at 12:50 AM, Peter Otten <__peter__ at web.de> wrote:

>
> > Hi guys can you tell me what is wrong with the second part of this
> > code(elif choice == '2'). When I type something other than 0-255, it
> > correctly asks again for an input but when I enter a number from 0-255 it
> > does nothing :
>
> It doesn't do nothing, it keeps running the while loop. Add a print() call
>
> >     elif choice == '2':
> >          denary2 = int(input("Please enter a denary number: "))
> >          remainder = ''
> >          while denary2 not in range(0,256):
> >              denary2 = int(input("Please enter a denary number: "))
> >              continue
> >          while denary2 in range(0,256):
>
>               print("XXX denary2 =",  denary2)
>
> >             remainder = str(denary2 % 2) + remainder
> >             denary2 >>= 1
> >          print("The result is",remainder)
>
> to see what's happening.
>
>
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--
regards,
Sarma.
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