[Tutor] Using subprocess on a series of files with spaces

[C Smith]

>for track, filename in enumerate(os.listdir(directory), 1):
It seems kinda counter-intuitive to have track then filename as
variables, but enumerate looks like it gets passed the filename then
track number. Is that correct and just the way enumerate works, a
typo, or am I missing something else here?

It is an ffmpeg error I am getting.
ffmpeg just gives its usual build information and the error is (for
each song title in the directory):
songTitleIsHere.flac: no such file or directory

So it looks like it is close to working because it finds the correct
file names, but doesn't recognize it for some reason.
Here is how I put in your code
import os, subprocess
directory = '/absolute/path/goes/here'
for track, filename in enumerate(os.listdir(directory), 1):
    pathname = os.path.join(directory, filename)
    subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])

So it goes to the right place, because every song title is listed out,
ffmpeg or the shell just don't recognize them correctly.

On Thu, Jul 31, 2014 at 6:35 PM, Steven D'Aprano <steve at pearwood.info> wrote:
> You may have already have solved your problem, unfortunately my
> emails are coming in slowly and out of order, but I have a suggestion:
>
> On Thu, Jul 31, 2014 at 03:53:48PM -0400, C Smith wrote:
>> I am on OSX, which needs to escape spaces in filenames with a backslash.
>
> Same as any other Unix, or Linux, or, indeed, Windows.
>
>> There are multiple files within one directory that all have the same
>> structure, one or more characters with zero or more spaces in the
>> filename, like this:
>> 3 Song Title XYZ.flac.
>> I want to use Python to call ffmpeg to convert each file to an .mp3.
>> So far this is what I was trying to use:
>> import os, subprocess
>> track = 1
>> for filename in os.listdir('myDir'):
>>     subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>>     track += 1
>
> I believe that your problem is *not* the spaces, but that you're passing
> just the filename and not the directory. subprocess will escape the
> spaces for you. Also, let Python count the track number for you. Try
> this:
>
>
> directory = '/path/to/the/directory'
> for track, filename in enumerate(os.listdir(directory), 1):
>     pathname = os.path.join(directory, filename)
>     subprocess.call(['ffmpeg', '-i', filename, str(track)+'.mp3'])
>
>
> I expect something like that will work. You should be able to pass
> either an absolute path (beginning with /) or a relative path starting
> from the current working directory.
>
> If this doesn't work, please show the full error that you receive. If it
> is a Python traceback, copy and paste the whole thing, if it's an ffmpeg
> error, give as much information as you can.
>
>
>
> --
> Steven
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