[Tutor] Python Programming

[D.V.N.Sarma డి.వి.ఎన్.శర్మ]

change the line

if answera == ["Oslo" or "oslo"]:

to

if answera == "Oslo" or  answera == "oslo":

and see if it works.

regards,
Sarma.


On Thu, Aug 28, 2014 at 12:27 AM, Alan Gauld <alan.gauld at btinternet.com>
wrote:

> On 27/08/14 14:40, Jake wrote:
>
>> To whom it may concern,
>> My name is Jake and I have recently started the GCSE computing course
>> with school.
>>
>
>  answera = input()
>> if answera == ["Oslo" or "oslo"]:
>>
>
> This doesn't do what you think it does.
>
> ["Oslo" or "oslo"]  is a list
>
> "Oslo" or "oslo"   is the content of the list and
> is a boolean expression which evaluates to True.
> (Each non-empty string is considered True by Python)
>
> So your 'if' line looks to Python like:
>
> if answera == [True]:
>
> But answera is a string so it will never equal a list
> with a single boolean value so you go to the else
> clause.
>
> A better way to do what you want is to convert the input
> to lowercase using the string lower() method and compare
> that to the string you want, like so:
>
> if answera.lower() == "oslo":
>
> If you need to check multiple possible answers you can use
> a list of strings and the 'in' operator like this:
>
> if answera.lower() in ['amsterdam', 'london', 'oslo']:
>
> HTH
> --
> Alan G
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/
> http://www.flickr.com/photos/alangauldphotos
>
>
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