[Tutor] Finding numeric day in a year...
alan.gauld at btinternet.com
Sat Jun 28 20:39:20 CEST 2014
On 28/06/14 18:59, Ken G. wrote:
> datecode = "20140101" # from database on file
> month = datecode[4:6]
> day = datecode[6:8]
> year = datecode[0:4]
use strptime() to parse dates, its much more reliable.
> datecode = year + "-" + month + "-" + day
> today = datecode
And use strftime() to format them...
> print today
> print "Day of year: ", datetime.date.today().strftime("%j")
This returns todays date whenever you run it.
It has nothing to do with the dates above.
But if you use strptime() to get the date from your string you should
then be able to use strftime to convert it to julian.
BTW You say you get it from "database on file".
Now if that is a real database such as SQLite you will find functions
there to convert it to julian at source... which is easier than reading
it as a string, parsing it, and then converting it back to a date again...
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