[Tutor] Finding numeric day in a year...[SOLVED]

[Ken G.]

On 06/28/2014 02:39 PM, Alan Gauld wrote:
> On 28/06/14 18:59, Ken G. wrote:
>
>> datecode = "20140101" # from database on file
>>
>> month = datecode[4:6]
>> day  = datecode[6:8]
>> year  = datecode[0:4]
>
> use strptime() to parse dates, its much more reliable.
>
>> datecode = year + "-" + month + "-" + day
>> today = datecode
>
> And use strftime() to format them...
>
>> print today
>> print
>>
>> print "Day of year: ", datetime.date.today().strftime("%j")
>
> This returns todays date whenever you run it.
> It has nothing to do with the dates above.
> But if you use strptime() to get the date from your string you should 
> then be able to use strftime to convert it to julian.
>
> BTW You say you get it from "database on file".
> Now if that is a real database such as SQLite you will find functions 
> there to convert it to julian at source... which is easier than 
> reading it as a string, parsing it, and then converting it back to a 
> date again...
>
>
> HTH

Ah, it is a Python database consisting of year-month-date and past drawn 
lotto numbers. I have just noticed that I am missing some twice weekly 
drawing. I am checking which one I am missing so far this year. Thanks 
to all that helps me
solved the puzzle.

Ken