[Tutor] (no subject)

[JEAN MICHEL]

thank you for the all advice I really appreciate it. I probably wasn't
 wasn't too clear when i first sent my email asking for help, my apologies
so let me better explain what i'm doing. I'm trying to write a program that
reads 3 class data files such as period1.txt, period2.txt. Inside those
files are the first name, last name, and 3 test scores from 3 different
students.

The format of the data files looks like this
Meagan. Hesse. 99. 99. 99

 My program is then suppose to take the average assign a grade and write
the results and also the students names in another txt folder

I've tried fixing some of the problems but it looks like it's still a work
in progress I'm not to sure whether i'm opening the data files right, can
you take a look at that part


def calcaverage(test1,test2,test3):
    for count in range(test1,test2,test3):
        curraverage=0
        curraverage=((test1[count]+ test2[count]+ test3[count])/3)
        currentaverage.append(curraverage)
        if curraverage>= 90:
            grade= "A"
            lettergrades.append(grade)
        elif curraverage >= 80 and curraverage < 90:
            grade= "B"
            lettergrades.append(grade)
        elif curraverage >= 70 and curraverage < 80:
            grade= "C"
            lettergrades.append(grade)
        elif curraverage < 70:
            grade= "F"
            lettergrades.append(grade)

name=[]
test1=[]
test2=[]
test3=[]
averagescore=[]
lettergrades=[]

with open ("period1.txt", 'r') as infile:
    for line in infile:
        values = line.split()
        name.append(values[0] + ','+ values[1])
        for line in infile:
            values = line.split()
            score1=float(values[2])
            test1.append(score1)
            for line in infile:
                values = line.split()
                score2=float(values[3])
                test2.append(score2)
                for line in inline:
                    values = line.split()
                    score3=float(values[4])
                    test3.append(score3)
averagescore=calcaverage(test1,test2,test3)

print(line)



On Wed, May 14, 2014 at 9:15 PM, Danny Yoo <dyoo at hashcollision.org> wrote:

> >         if curraverage>= 90:
> >             grade= "A"
> >             lettergrades.append(grade)
> >         else:
> >             if curraverage >= 80 and curraverage < 90:
> >                 grade= "B"
> >                 lettergrades.append(grade)
> >             else:
> >                 if curraverage >= 70 and curraverage < 80:
> >                     grade= "C"
> >                     lettergrades.append(grade)
> >                 else:
> >                     if curraverage < 70:
> >                         grade= "F"
> >                         lettergrades.append(grade)
>
>
> Just wanted to note that this style of cascading if statements is a
> little unusual here.  Since you know that only one of the tests is
> going to be true, you can use a more parallel structure.
>
> That is, if you're doing something like:
>
> ##################
> if test1:
>    ...
>    else:
>         if test2:
>             ...
>         else:
>             if test3:
>                 ...
>             else:
>                 ...
> ##################
>
> and if you know that test1, test2, and test3 don't overlap, you can
> express this as:
>
>
> ##################
> if test1:
>     ...
> elif test2:
>     ...
> elif test3:
>     ...
> else:
>     ...
> ##################
>
> and avoid the Tower of Pisa-style code.
>
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