[Tutor] R: Tutor Digest, Vol 123, Issue 65

jarod_v6 at libero.it jarod_v6 at libero.it
Tue May 27 18:20:22 CEST 2014


Thanks so much for the help! and suggestions I not use dictionary because I  
have some items are repeated inside the list


>----Messaggio originale----
>Da: tutor-request at python.org
>Data: 27/05/2014 12.00
>A: <tutor at python.org>
>Ogg: Tutor Digest, Vol 123, Issue 65
>
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>Today's Topics:
>
>   1. Help on  best way to check resence of item inside list
>      (jarod_v6 at libero.it)
>   2. Re: Help on  best way to check resence of item inside list
>      (Mark Lawrence)
>
>
>----------------------------------------------------------------------
>
>Message: 1
>Date: Tue, 27 May 2014 10:05:30 +0200 (CEST)
>From: "jarod_v6 at libero.it" <jarod_v6 at libero.it>
>To: tutor at python.org
>Subject: [Tutor] Help on  best way to check resence of item inside
>	list
>Message-ID: <975274200.13645911401177930495.JavaMail.actor at webmail48>
>Content-Type: text/plain;charset="UTF-8"
>
>Dear All
>
>clubA= ["mary","luke","amyr","marco","franco","lucia", "sally","genevra","
>electra"]
>clubB= ["mary","rebecca","jane","jessica","judit","sharon","lucia", "sally","
>Castiel","Sam"]
>
>I have a list of names that I would to annotate  in function of presence in
>different clubs:
>
>my input files is a long file where I have this :
>
>mary
>luke
>luigi
>jane
>jessica
>rebecca
>luis
>################################################?
>
>with open("file.in") as p:
>mit = []
>for i in p:
>   lines =i.strip("\n").split("\t")
>   if  (lines[0] in clubA:
>              G =lines[-1] +["clubA"]
>   else:
>           G = lines[-1] +["no"]  
>mit.append(G)
>  
>
>for i in mit:
>   if i.strip("\n").split("\t")[0] in clubB:
>         G =lines[-1] +["clubB"]
>   else:
>           G = lines[-1] +["no"]  
>  finale.append(G)
>###############################################################
>I just wonder if is appropriate to use a loops to check if is present the
>value on a list. Is it the right way? I can use a dictionary because I have
>many repeated names.
>
>In the end I wan to have
>
>
>mary  clubA clubB
>luke clubA
>luigi  no
>Thanks in advance for any help
>
>
>------------------------------
>
>Message: 2
>Date: Tue, 27 May 2014 09:48:27 +0100
>From: Mark Lawrence <breamoreboy at yahoo.co.uk>
>To: tutor at python.org
>Subject: Re: [Tutor] Help on  best way to check resence of item inside
>	list
>Message-ID: <lm1jgs$o8h$1 at ger.gmane.org>
>Content-Type: text/plain; charset=UTF-8; format=flowed
>
>On 27/05/2014 09:05, jarod_v6 at libero.it wrote:
>> Dear All
>>
>> clubA= ["mary","luke","amyr","marco","franco","lucia", "sally","genevra","
>> electra"]
>> clubB= ["mary","rebecca","jane","jessica","judit","sharon","lucia", 
"sally","
>> Castiel","Sam"]
>>
>> I have a list of names that I would to annotate  in function of presence in
>> different clubs:
>>
>> my input files is a long file where I have this :
>>
>> mary
>> luke
>> luigi
>> jane
>> jessica
>> rebecca
>> luis
>> ################################################?
>>
>> with open("file.in") as p:
>> mit = []
>> for i in p:
>>     lines =i.strip("\n").split("\t")
>>     if  (lines[0] in clubA:
>>                G =lines[-1] +["clubA"]
>>     else:
>>             G = lines[-1] +["no"]
>> mit.append(G)
>>
>>
>> for i in mit:
>>     if i.strip("\n").split("\t")[0] in clubB:
>>           G =lines[-1] +["clubB"]
>>     else:
>>             G = lines[-1] +["no"]
>>    finale.append(G)
>> ###############################################################
>> I just wonder if is appropriate to use a loops to check if is present the
>> value on a list. Is it the right way? I can use a dictionary because I have
>> many repeated names.
>>
>> In the end I wan to have
>>
>>
>> mary  clubA clubB
>> luke clubA
>> luigi  no
>> Thanks in advance for any help
>
>You can use the in keyword to check for an item in a list.  However a 
>very quick glance at your code suggests that you could cut out the list 
>completely and do the same using the in keyword against your dict. 
>Better still I think the defaultdict is what you need here, I'll leave 
>you to look it up as I must dash :)
>
>
>-- 
>My fellow Pythonistas, ask not what our language can do for you, ask 
>what you can do for our language.
>
>Mark Lawrence
>
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>End of Tutor Digest, Vol 123, Issue 65
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