[Tutor] introspection

[Alex Kleider]

On 2015-04-20 09:15, Joel Goldstick wrote:
> On Mon, Apr 20, 2015 at 11:24 AM, Alex Kleider <akleider at sonic.net> 
> wrote:
>> Does python provide the introspective ability to retrieve the name to 
>> which
>> an object is bound?
>> 
>> For example:
>> $ python3
>> Python 3.4.0 (default, Apr 11 2014, 13:05:18)
>> [GCC 4.8.2] on linux
>> Type "help", "copyright", "credits" or "license" for more information.
>>>>> 
>>>>> a = 69
>>>>> print("Identifier <{}> is bound to {}.".format(a.__name__, a))
>> 
>> Traceback (most recent call last):
>>   File "<stdin>", line 1, in <module>
>> AttributeError: 'int' object has no attribute '__name__'
>> 
>> 
> An object can be bound to multiple names.  Within a namespace you can
> use locals to see names, then compare various names like so:
>> 
>>>> a = 3
>>>> b = 6
>>>> c = a
>>>> locals()
> {'a': 3, 'c': 3, 'b': 6, '__builtins__': <module '__builtin__'
> (built-in)>, '__package__': None, '__name__': '__main__', '__doc__':
> None}
>>>> a is b
> False
>>>> a is c
> True

Showing my desired use case might make my question more understandable:
def debug(var_name):
     if args["--debug"]:
         print("Identifier <{}> is bound to: {}"
             .format(var_name.__name__, repr(var_name)))
I don't think the built in locals() can help me.
Thanks all the same.
Alex