[Tutor] updating a dictionary
Chris Stinemetz
chrisstinemetz at gmail.com
Fri Feb 20 18:56:53 CET 2015
I am getting closer. I think I have figured out the logic. I just have a
quick question. How do you access key:values in a nested dictionary?
MOL02997_C': [{'2': '0', '7': '0', '8': '0', '9': '0'}]}
say I want to access the key:value 8:0
print dict['MOL02997_C']['8'] doesn't seem to work.
Thanks in advance.
On Thu, Feb 19, 2015 at 5:10 PM, Alan Gauld <alan.gauld at btinternet.com>
wrote:
> On 19/02/15 22:50, Emile van Sebille wrote:
>
> if cell.endswith(suffix, 14, 16) is False:
>>>
>>
>> ... so they'll never end with numeric values. Further, "".endswith()
>> accepts only one argument so you ought to get an error on this line.
>>
>
> Sorry Emile, The OP is correct.
>
> ######################
> >>> help(''.endswith)
> endswith(...) method of builtins.str instance
> S.endswith(suffix[, start[, end]]) -> bool
>
> Return True if S ends with the specified suffix, False otherwise.
> With optional start, test S beginning at that position.
> With optional end, stop comparing S at that position.
> suffix can also be a tuple of strings to try.
> #######################
>
> The tuple is the set of suffices and the numbers are the
> start/end points. Its not often seen like that but the
> OP is quite correct.
>
>
> The test against False is unusual it woyuld normally look like
>
> if not cell.endswith(suffix, 14, 16):
>
> but that is just a style issue.
>
>
> --
> Alan G
> Author of the Learn to Program web site
> http://www.alan-g.me.uk/
> http://www.amazon.com/author/alan_gauld
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>
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