[Tutor] Risk Dice Program
breamoreboy at yahoo.co.uk
Wed Jan 28 01:09:31 CET 2015
On 27/01/2015 23:09, Alan Gauld wrote:
> On 27/01/15 19:12, Dillon Cortez wrote:
>> problem is that if any of the offensive dice is bigger
> > than only one of the defensive dice,
>> the program shows the offense as the winner,
>> def winner():
>> if o_die1 > d_die1 or d_die2:
>> print "The offense has won"
> The problem is that the computer reads that differently to you.
> It sees it as
> if (o_die1 > d_die1) or d_die2:
> Now, due to how Python evaluates logical 'or' expressions,
> it knows that if the first part is True it doesn't need to evaluate
> the second part so, if d_die1 is less that o_die1 then it returns True
> and all is well.
> But if d_die1 is greater that o_die1 it then returns the value
> of the second expression in the 'or', namely d_die2. Which is not
> what you want in this case.
> To get round that you need to explicitly compare o_die1
> to both values:
> if (o_die1 > d_die1) or (o_die1 > d_die2):
> You don't strictly need the parens but I prefer to keep them there
> to remind me of what's going on.
I consider the chained comparisons shown here
https://docs.python.org/3/reference/expressions.html#not-in to be far
more Pythonic. It also avoids the superfluous brackets which always
drive me around the bend.
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.
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