[Tutor] Risk Dice Program
alan.gauld at btinternet.com
Wed Jan 28 02:28:52 CET 2015
On 28/01/15 00:09, Mark Lawrence wrote:
>> To get round that you need to explicitly compare o_die1
>> to both values:
>> if (o_die1 > d_die1) or (o_die1 > d_die2):
> I consider the chained comparisons shown here
> https://docs.python.org/3/reference/expressions.html#not-in to be far
> more Pythonic. It also avoids the superfluous brackets which always
> drive me around the bend.
Sorry Mark, I'm missing something. How would chained comparisons work
for this case? Especially a not-in?
You can avoid the compound test using any() and a generator as per my
earlier post but I can't think how a chained test would work here?
But it is getting late...
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