[Tutor] Risk Dice Program

[Alan Gauld]

On 28/01/15 00:09, Mark Lawrence wrote:

>> To get round that you need to explicitly compare o_die1
>> to both values:
>>
>>       if (o_die1 > d_die1) or (o_die1 > d_die2):
>>
>
> I consider the chained comparisons shown here
> https://docs.python.org/3/reference/expressions.html#not-in to be far
> more Pythonic.  It also avoids the superfluous brackets which always
> drive me around the bend.

Sorry Mark, I'm missing something. How would chained comparisons work
for this case? Especially a not-in?
You can avoid the compound test using any() and a generator as per my 
earlier post but I can't think how a chained test would work here?

But it is getting late...

-- 
Alan G
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