[Tutor] Unexpected results using enumerate() and .split()

[Dave Angel]

On 03/31/2015 04:23 PM, boB Stepp wrote:
> The following behavior has me stumped:
>
> Python 2.7.8 (default, Jun 30 2014, 16:03:49) [MSC v.1500 32 bit
> (Intel)] on win32
> Type "copyright", "credits" or "license()" for more information.
>>>> L = ['#ROI:roi_0', '#TXT:text_0', '#1:one^two^three']
>>>> for i, item in enumerate(L):
>          subitems = item.split(':')
>          if subitems[0] == '#ROI':
>                  print subitems[1]
>          if subitems[0] == '#TXT':
>                  print subitems[1]
>          if subitems[0] == '#1' or '#2':

I think what you meant here was:
            if subitems[0] == "#1" or subitems[0] == "#2":

>                  print subitems[1]

Study the first expression and see if you can figure out what the 
difference is.  If it's not clear, then make a simpler program just to 
test a compound if, and we'll all talk about it.

>
> roi_0ail
> roi_0
> text_0
> text_0
> one^two^three
>>>>
>
> My desired output was:
>
> roi_0
> text_0
> one^two^three
>
> Oh, wonderful founts of wisdom, where is my understanding lacking?
>
> BTW, I copied and pasted the above into my Gmail window, but it
> removed the indentation that was present in the interpreter. I added
> spaces manually to get it appear as it did in the interpreter. Anyone
> know why Gmail does that to my copy and paste?
>

Buggy, I guess.  Why not use a program like Thunderbird, which is free 
and available on most PC operating systems?

(Unfortunately, it's not on Android)

-- 
DaveA