[Tutor] Creating lists with 3 (later4) items occuring only once

[Alan Gauld]

On 18/09/15 16:41, marcus lütolf wrote:

>>>> s = ['ab','ac','bc','ad','ae','de']
>>>> for startlist in itertools.combinations(s, 3):

> How can I concatenate the 20 lists in oder to get one count for each of the items in s , for example 10 for 'ab'?


If I understand you correctly, something like this:

 >>> counts = {'ab':0,'ac':0,'bc':0,'ad':0,'ae':0,'de':0}
 >>> for combo in it.combinations(counts.keys(),3):
...     for pair in combo:
...        counts[pair] += 1
...
 >>> counts
{'ac': 10, 'ab': 10, 'ae': 10, 'ad': 10, 'bc': 10, 'de': 10}

Is that what you want?

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Alan G
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