[Tutor] unknown syntax error

[bob gailer]

On 12/11/2016 11:30 AM, oliver patterson wrote:
> hey i dont know if this is the right place but i was just coding in idle and kept getting this syntax error and i can not see m to fix it here is my bit of code:
>
> my_age=14
> age=input("How old are you?:")
> print("type start()")
> def start():
>      print("hey")
>      if age == my_age:
>          print("i'm",age,"too")
>          else:
>              if age < 14:
>                  print(" i'm older that you i'm",my_age,":)")
>                  else:
>                      print("your older than me i'm",my_age,":(")
>
>
>
> please help thank you.
IDLE's way of reporting some errors is different than the standard 
traceback, so you may not be able to follow Bob Stepp's advice.

When I select Run on your module I see the first "else" highlighted in 
red, and the invalid syntax message.

If you undent the else blocks giving:

my_age=14
age=input("How old are you?:")
print("type start()")
def start():
     print("hey")
     if age == my_age:
         print("i'm",age,"too")
     else:
         if age < 14:
             print(" i'm older that you i'm",my_age,":)")
         else:
             print("your older than me i'm",my_age,":(")

the program will pass the syntax checks. When you run it it will fail:

How old are you?:as
type start()
 >>> start()
hey
Traceback (most recent call last):
   File "<pyshell#0>", line 1, in <module>
     start()
   File "C:/Python35/oliver.py", line 9, in start
     if age < 14:
TypeError: unorderable types: str() < int()
 >>>

Can you figure out why? Can you propose a fix?

If you want to impress potential employers I recommend cleaning up your 
English.