[Tutor] __getitem__

monikajg at netzero.net monikajg at netzero.net
Wed Nov 23 19:50:03 EST 2016

```Hi:
Thank you very much for ALL your postings. They help a lot and now things make sense.
Thank you
Monika

---------- Original Message ----------
From: Alan Gauld via Tutor <tutor at python.org>
To: tutor at python.org
Subject: Re: [Tutor] __getitem__
Date: Wed, 23 Nov 2016 22:25:08 +0000

On 23/11/16 12:25, monikajg at netzero.net wrote:

> I have two questions in regards to below code:
> 1. largest is a list, not a list of lists.
> [('deit', 4), ('acer', 3), ('aceilmr', 2), ('arst', 2)]
> so why when I do largest[0] I get the whole list again,

I don't know you will need to show us some real code.
Ideally input at the >>> prompt.

> 2. largest = [sorted(analist, key=lambda analist: analist[1], reverse=True)]
> brings back the same result as:
> largest = [sorted(analist, key=lambda d: d[1], reverse=True)]
> and the same result as:
> largest = [sorted(analist, key=lambda x: x[1], reverse=True)]

Yes because it doesn't matter what you call the parameter of the lambda,
it's like any other function:

All of these functions are identical they always do the same
regardless of what you call the parameter. Remember a lambda
is just a shortcut for a function

key = lambda d: d[1]

is identical to

def key(d): return d[1]

and

key = lambda analist: analist[1]

is identical to

def key(analist): return analist[1]

Just like the add2() examples it doesn't matter what
name you use for the parameter.

> ...but where does it get the x, what is the value of x?

See my other post about how sorted() works.

--
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
Follow my photo-blog on Flickr at:
http://www.flickr.com/photos/alangauldphotos

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