[Tutor] Tkinter layout question

[Alan Gauld]

On 24/04/17 01:50, Phil wrote:
> On Mon, 24 Apr 2017 09:24:55 +1000
> Phil <phil_lor at bigpond.com> wrote:
>
>> On Sun, 23 Apr 2017 09:39:54 +0200
>> Sibylle Koczian <nulla.epistola at web.de> wrote:
>>
>>> Am 20.04.2017 um 14:43 schrieb Alan Gauld via Tutor:
>>>> Its not too bad you can map the large 9x9 table to the smaller
>>>> units using divmod()
>>>>
>>>> So the 7th element becomes
>>>> divmod(7) -> 2,1
>>>>
>>>
>>> Should be divmod(7, 3), shouldn't it?

Yes, of course, sorry about that!
The 3 of course is the number of items per cell (3x3)

> Say I want the 7th cell in the first line of a 9 x 9 grid,
 > that would be x = 7, y = 1.

But you want it mapped to a cell/item pair...

divmod(7,3) -> 2,1


The 3rd cell, 2nd item which is wrong for the item part.
So you need to use:

2, 1-1

Taking item 4 in your 9x9,

divmod(4,3) -> 1,1  cell 1 item 1 so again you need
to subtract 1

So we can write

def map_dimension_to_cell(index):
     cell,item = divmod(index,3)
     return cell,item-1

And luckily for us that works even on exact boundaries
because cell[-1] is the last item in the cell!

Mapping columns is exactly the same.

Now the only problem is to map your notional 9x9 table 9
indexing from 1 to a Python 9x9 indexing from zero.
The easiest way is to add 1 to the input index:

def map_index_to_cell(index):
     cell,item = divmod(index+1,3)
     return cell,item-1

You can now pass in the x or y index from your
python 9x9 table to get the cell/item indexes
in your GUI like so:

cell_x,x = map_index_to_cell(x_index)
cell_y,y = map_index_to_cell(y_index)

cell = sudoku_grid[cell_x,cell_y]
item = cell[x,y]

All untested but I think that should work...
And you could wrap that up as a pair of get/set
functions if you so wished.

def get_sudoku_grid(x,y):
    # code above
    return item

def set_sudoku_grid(x,y,value):
     #code above
     item = value

Sorry for the late response, I'm on a vacation so
not checking mail that often...

HTH

Alan G