[Tutor] change the position and updated

[Neeraj Sharma]

Hi,

Find the code below

c = [(12, 45), (1234, 567), (12345, 0), (678, 123456)]

max_length = 0
for key,value in c:
     list1 = []
     list2 = []
     for i in str(key):
             list1.append(i)
     for j in str(value):
             list2.append(j)
     if (len(list1)>len(list2)): max_length = len(list1)
     else: max_length = len(list2)
     for i in range(0,max_length):
             pass
     result=""
     for i in range(0,max_length):
         try: result = result + list1[i]
         except: pass
         try: result = result + list2[i]
         except: pass
     print int(result)

On Wed, Apr 26, 2017 at 12:13 PM, Sarika Shrivastava <
sarika1989.08 at gmail.com> wrote:

> Input :
> c=[(12,45),(1234,567),(12345,0),(678,123456)]
>
> #o/p==1425
> #o/p==1526374
> #0/p==102345
> #o/p===617283456
>
> Question explanation:
>
> in list c we have some tuples so I need to take tuple value one by one and
> change the position of value like wise
>
>  first tuple value (12 ,45) then  then 1 we pick up append on 4 So it make
>  14 after tat 2 we pick and append on 5 so 25 then final o/p is 1425 ,
>
> Please check output also...
>
> --
> Best regards,
>
> Sarika Shrivastava
> Associate Engineer
>
> Continental Automotive Components (India) Pvt. Ltd.,
> 8th Floor, Gold Hill Supreme Software Park,
> Plot No. 21, 22, 27 & 28, Shanthipura Road,
> Electronics City, Phase II, Hosur Road,
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>
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-- 

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*Neeraj Sharma+91-9873741375*