[Tutor] Problem with 'IF' condition

[Alan Gauld]

Please always reply all to include the tutor list

On 04/12/17 14:29, a.ajmera at incycleautomation.com wrote:
> Thank you so much for your quick reply.
> I don't think there are any white space errors.

Don't guess, prove it.
To do that you *must* use repr() otherwise print() will hide the whitespace.

Also do you have a valid reason for reading the first file then
overwriting it?
It seems like wasted effort unless you plan onm doing something
with the original content at some point in the future?

>  
> However, Whatever you understood is exactly same what I tried to
> explain in my email.
> In this email I have attached output screen shot.
> abb and nao contain exactly same value(you can see in screen shot, as
> I print values). 
> But, I don't understand as it is printing same values(in abb and nao);
> it should give output "positions are same".
> But it doesnot.
>  
> Please let me know if you find any errors.
>  
> Best Regards,
> Achyut Ajmera 
>  
>  
>
>     --------- Original Message ---------
>     Subject: Re: [Tutor] Problem with 'IF' condition
>     From: "Alan Gauld via Tutor" <tutor at python.org>
>     Date: 12/1/17 12:33 pm
>     To: tutor at python.org
>
>     On 01/12/17 14:02, a.ajmera at incycleautomation.com wrote:
>
>     > - If you see in my code, I'm writing to "test1.txt" and saving
>     that value in "nao" as well.
>     > On the other side, I'm reading from "test3.txt" and saving that
>     value in "abb" just like above.
>     >
>     > Now, my goal is to compare these two variables nao & abb. As it
>     written below.
>     > However, result never gives me "true" when actually this both
>     variable contain same values.
>
>     Are you absolutely sure they are the same? Have you checked, for
>     example
>     for newline characters or other whitespeace?
>     You could do that by printing the repr() of the values:
>
>     print repr(nao), repr(abb)
>
>     Now simplifying your code slightly:
>
>     > x = "C:/FTP_Folder/test1.txt"
>     > f = open(x)
>     > r = f.read(500)
>     > f.close()
>
>     > f1 = open(x,'w')
>     > z = f1.write("1")
>     > f1.close()
>
>     Note that this will have deleted everything in x
>     and replaced it with "1"
>
>     > f = open(x)
>     > r0 = f.read(500)
>
>     r0 will now contain '1'
>
>     > nao = r0
>
>     As will nao
>
>     > f.close()
>
>     > y = "C:/FTP_Folder/test3.txt"
>     > f2 = open(y)
>     > r1 = f2.read(500)
>     > abb = r1
>
>     abb now contains whatever was in test3.txt.
>     Did it contain '1'?
>
>     > if nao == abb:
>     > print("Positions are same")
>     > print r, r1
>
>     r contains the original contents of test1
>     r1 contains the content of test3
>
>     > else:
>     > print("not same")
>     > print nao, abb
>
>     whereas nao contains '1' and abb contains the
>     same as r1
>
>     Is my interpretation what you see, and is it what
>     you expect?
>
>     In future with thee kinds of issues its good
>     to include an actual cut n paste of the program
>     output.
>
>     -- 
>     Alan G
>     Author of the Learn to Program web site
>     http://www.alan-g.me.uk/
>     http://www.amazon.com/author/alan_gauld
>     Follow my photo-blog on Flickr at:
>     http://www.flickr.com/photos/alangauldphotos
>
>
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-- 
Alan G
Author of the Learn to Program web site
http://www.alan-g.me.uk/
http://www.amazon.com/author/alan_gauld
Follow my photo-blog on Flickr at:
http://www.flickr.com/photos/alangauldphotos