[Tutor] Problem with 'IF' condition
alan.gauld at yahoo.co.uk
Mon Dec 4 12:05:35 EST 2017
Please always reply all to include the tutor list
On 04/12/17 14:29, a.ajmera at incycleautomation.com wrote:
> Thank you so much for your quick reply.
> I don't think there are any white space errors.
Don't guess, prove it.
To do that you *must* use repr() otherwise print() will hide the whitespace.
Also do you have a valid reason for reading the first file then
It seems like wasted effort unless you plan onm doing something
with the original content at some point in the future?
> However, Whatever you understood is exactly same what I tried to
> explain in my email.
> In this email I have attached output screen shot.
> abb and nao contain exactly same value(you can see in screen shot, as
> I print values).
> But, I don't understand as it is printing same values(in abb and nao);
> it should give output "positions are same".
> But it doesnot.
> Please let me know if you find any errors.
> Best Regards,
> Achyut Ajmera
> --------- Original Message ---------
> Subject: Re: [Tutor] Problem with 'IF' condition
> From: "Alan Gauld via Tutor" <tutor at python.org>
> Date: 12/1/17 12:33 pm
> To: tutor at python.org
> On 01/12/17 14:02, a.ajmera at incycleautomation.com wrote:
> > - If you see in my code, I'm writing to "test1.txt" and saving
> that value in "nao" as well.
> > On the other side, I'm reading from "test3.txt" and saving that
> value in "abb" just like above.
> > Now, my goal is to compare these two variables nao & abb. As it
> written below.
> > However, result never gives me "true" when actually this both
> variable contain same values.
> Are you absolutely sure they are the same? Have you checked, for
> for newline characters or other whitespeace?
> You could do that by printing the repr() of the values:
> print repr(nao), repr(abb)
> Now simplifying your code slightly:
> > x = "C:/FTP_Folder/test1.txt"
> > f = open(x)
> > r = f.read(500)
> > f.close()
> > f1 = open(x,'w')
> > z = f1.write("1")
> > f1.close()
> Note that this will have deleted everything in x
> and replaced it with "1"
> > f = open(x)
> > r0 = f.read(500)
> r0 will now contain '1'
> > nao = r0
> As will nao
> > f.close()
> > y = "C:/FTP_Folder/test3.txt"
> > f2 = open(y)
> > r1 = f2.read(500)
> > abb = r1
> abb now contains whatever was in test3.txt.
> Did it contain '1'?
> > if nao == abb:
> > print("Positions are same")
> > print r, r1
> r contains the original contents of test1
> r1 contains the content of test3
> > else:
> > print("not same")
> > print nao, abb
> whereas nao contains '1' and abb contains the
> same as r1
> Is my interpretation what you see, and is it what
> you expect?
> In future with thee kinds of issues its good
> to include an actual cut n paste of the program
> Alan G
> Author of the Learn to Program web site
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