[Tutor] Using numpy stack functions

[Bruhnke, Angelica]

Hi,


I'm new to python programming so this question will probably be a no brainer for the experienced programmer. I'm trying to create a 10x10 array of zeros and then framing it with a border of ones.


Output should look like this:

[[ 1. 1. 1. 1. 1. 1. 1. 1. 1. 1. 1. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 0. 0. 0. 0. 0. 0. 0. 0. 0. 0. 1.]

[ 1. 1. 1. 1. 1. 1. 1. 1. 1. 1. 1. 1.]]



This is the code I've written:

a = np.ones ((1,10))

print a

b = np.zeros ((10,10))

print b

c = np.vstack ((b,a))

print c


This is my output:

[[ 1.  1.  1.  1.  1.  1.  1.  1.  1.  1.]]
[[ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]]
[[ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.  0.  0.  0.]
 [ 1.  1.  1.  1.  1.  1.  1.  1.  1.  1.]]?

As you can see I have too many zeros once I stack them and don't have the ones framing the sides vertically.

Any guidance on where I'm going astray?

Much appreciated,

A.B.