[Tutor] Query: lists

[Nitin Madhok]

Deepti,

What you’re seeing happens because you are making changes (words.remove(z)) to the list while you are iterating over it (for z in words). If your goal is to print the original words, removed words and original words without removed words, you could do something like this using sets:

words = ['bbb', 'ccc', 'axx', 'xzz', 'xaa']

def front_x(words):
 # +++your code here+++
 removed_words = []
 for word in words:
   if word.startswith('x'):
     removed_words.append(word)
     print 'word is', word
 print 'original', sorted(words)
 print 'new', sorted(removed_words)
 print sorted(list(set(removed_words + words)))

If you also wanted to get the original words after removing the removed_words, you could print them like this:
print 'original - new', list(set(words) - set(removed_words))

Or you could even use list comprehension like this:
print 'original - new', [word for word in words if word not in removed_words]

--

Thanks,
Nitin Madhok
Clemson University

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> On Aug 14, 2018, at 4:11 AM, Deepti K <kdeepti2013 at gmail.com> wrote:
> 
> when I pass ['bbb', 'ccc', 'axx', 'xzz', 'xaa'] as words to the below
> function, it picks up only 'xzz' and not 'xaa'
> 
> def front_x(words):
>  # +++your code here+++
>  a = []
>  b = []
>  for z in words:
>    if z.startswith('x'):
>      words.remove(z)
>      b.append(z)
>      print 'z is', z
>  print 'original', sorted(words)
>  print 'new', sorted(b)
>  print sorted(b) + sorted(words)
> 
> Thanks,
> Deepti
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