[Tutor] What is day of week from either 20180211 or 02112018 (SOLVED)

[Ken Green]

On 02/06/2018 03:36 PM, Mark Lawrence wrote:
> On 06/02/18 19:45, Ken Green wrote:
>> Greeting: I have been trying to determine the day of
>> the week when inputting year + month + date. I have
>> not yet been able to determine what is really needed
>> for datetime and later on the date in the program below.
>> Running Python 2.7 on Ubuntu 16.04. Thanks.
>> ===========================================
>> # A_Weekday.py
>> from datetime import date
>> year = "2018"
>> monthdate = raw_input ("Enter the month and date (MDD or MMDD): ")
>> print
>> if (len(monthdate)) == 3:
>>      month = monthdate[0:1]
>>      month = "0" + month
>>      day  = monthdate[1:3]
>> else:
>>      month = monthdate[0:2]
>>      day  = monthdate[2:4]
>> print month, day, year; print
>> print year, month, day; print
>> datecode = year + month + day
>> print datecode
>> print
>> answer = datetime.date(year, month, day).weekday()
>> print answer
>> ==================================================
>> Error message below:
>> Enter the month and date (MDD or MMDD): 211
>> 02 11 2018
>> 2018 02 11
>> 20180211
>> Traceback (most recent call last):
>>    File "A_Weekday.py", line 20, in <module>
>>      answer = datetime.date(year, month, day).weekday()
>> NameError: name 'datetime' is not defined
>>
>
> There's no need for the `datetime` as you've imported `date` directly 
> into the namespace.  Correct that problem and you'll still fail as 
> you're passing strings instead of integers.  I'd just force your 
> `monthdate` to be MMDD and pass that into `strptime` with `year`.
>
> >>> year = '2018'
> >>> monthdate = '0211' # skipping the input code.
> >>> from datetime import datetime
> >>> datetime.strptime(year + monthdate, '%Y%m%d')
> datetime.datetime(2018, 2, 11, 0, 0)
> >>> datetime.strptime(year + monthdate, '%Y%m%d').weekday()
> 6
>
Thanks. I already got it up and running. Much appreciated.