[Tutor] help with code
Leslie SimondeMontfort
mihsh at yahoo.com
Sat Mar 10 23:20:58 EST 2018
Hi, I wondered if there is someone that can help me with this code. Thank you, Leslie
## Text menu in Python
def print_menu(): ## Your menu design here
print 30 * "-" , "MENU" , 30 * "-"
print "1. Menu login 1"
print "2. Menu create an account 2"
print "3. Menu list all accounts 3"
print "4. Quit"
print 67 * "-"
loop!=4
while loop: ## While loop which will keep going until loop = False
print_menu() ## Displays menu
choice = input("Enter your choice [1-4]: ")
if choice==1:"Menu login 1"
count = 0
while True:
def User():
login = raw_input("Enter login name: ")
passw = raw_input("Enter password: ")
# check if user exists and login matches password
if login in users and users[login] == passw:
print "\nLogin successful!\n"
else:
print "\nUser doesn't exist or wrong password!\n"
if choice == 3:
print("Too many attempts.")
exit()
for val in "string":
if val == "i":
break
print(val)
print("The end")
if choice==2:
print " Menu create an account 2"
def main():
register()
def register():
username = input("Please input your desired username ")
password = input("Please input your desired password ")
if not username or not password:
print "Enter a valid username and password..."
users = c.get_all_users()
userList = users['list_users_response']['list_users_result']['users']
if username in userList:
print "username already exist"
else:
# I just want to create if fields are not empty and if username dont exist
c.create_user(username)
file = open("credential.txt","a")
file.write(username)
file.write(" ")
file.write(password)
file.close()
login()
if choice==3:
def login():
check = open("credential.txt","r")
username = input("Please enter your username")
password = input("Please enter your password")
def thank_you():
print("Thank you for signing up at our website!.")
elif choice == "q":
exit()
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