[Tutor] overlapping tuples

[David L Neil]

On 27/02/20 5:44 AM, Narasimharao Nelluri wrote:
> I got stuck at below problem for couple of days, can you guys help tp solve
> this problem.

This seems like a 'homework' assignment. Please declare it as such, so 
that we know to help you along your Python learning path...


>    if overlap is None:
>      overlap = []

Good technique!
- although question need for a second parameter at all?


>    for fir,sec in zip(old_list,old_list[1:]):
> 
>      if fir[1] >= sec[0] and fir[1] <=sec[1]:
>        overlap.append(fir)
> 
>      if sec[0] >= fir[0] and sec[1] <= fir[1]:
>        overlap.append(sec)

Please write your understanding of the above, more-or-less in English as 
if you were instructing another person (pseudo-code).

Second question (after you've tackled the above): are you preferring to 
use different words in the explanation from those used for variable 
names in the code? Room for code-improvement there?


>    print(overlap)

Recommend instead of printing 'inside', returning the result of the 
function. Then your main-line can change from - to -:


> list1 = [(1,10),(15,20),(101,110)]
> tuple_overlap(list1)

overlaps = tuple_overlap( [(1,10),(15,20),(101,110)] )
print( "Overlap 1 =", overlaps )


Plus, free bonus! Should you ever wish to use tuple_overlap() within 
some other function, it will be ready to deliver...


In fact (free ultra-bonus!) you have expected results in-mind (which you 
worked-out 'manually' before-hand - another good practice!), so you 
could ask Python to check/test for you:

assert overlaps == [(1, 20), (15, 20)]	# second test

Will leave it to you to note what happens when the assert-ion ('this is 
what I believe to be true') is correct, and what when it proves wrong...

(there are whole Python libraries to accomplish 'automated testing', 
which you could research later - but for now, simple is sweet!)
-- 
Regards =dn