[Tutor] Using break, else with for loop

[Alan Gauld]

On 11/10/2020 08:58, Alan Gauld via Tutor wrote:

> That's a valid solution.
> A slightly shorter version is:
> 
> if any(n%2 for n in l):
>    print("Odd no found in list")

I meant to add, that this has the advantage of explicitly
expressing the intent of the code in the function.

-- 
Alan G
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