[Tutor] A Multiple Concatenation Problem

[Mark Lawrence]

On 19/09/2020 22:09, Stephen P. Molnar wrote:

> 
>     input              output
> <ligand>  ----> ligand .i.log   where i in range(1,11)
> 

So you want:-

ligand1.1.log
ligand1.2.log
ligand1.3.log
...
ligand31.8.log
ligand31.9.log
ligand31.10.log

in which case you need nested loops something like:-

filenames = []
with open('Ligand.list') as infile:
     for ligand in infile:
         for suf in range(1, 11):
             filename = f"{ligand[:-1]}.{suf}.log" # IIRC how to strip 
EOL :)
             filenames.append(filename)
             print(filename)

Have we got there?

-- 
My fellow Pythonistas, ask not what our language can do for you, ask
what you can do for our language.

Mark Lawrence