[Tutor] Using optional else with for loop

[Manprit Singh]

Dear sir ,

Consider a problem where i have to  print first n prime numbers. Value of n
will be provided by the user through the keyboard. I have written the code
for this problem  as given below :

def isprime(x):
    for i in range(2, int(x**0.5) + 1):
        if x % i == 0 :
            return False
    else:
        return True

n = int(input("Enter a number"))
i = 2
while n > 0:
    if isprime(i):
        print(i)
        n = n - 1
    i = i + 1

Providing n = 6  through keyboard gives the answer as given below, which is
correct

2
3
5
7
11
13

My Question is regarding the function isprime() which returns True if number
is prime, else returns false . My Logic is if the number is not prime,
x % i == 0 inside the for loop will evaluate to True at some point of time.

Now return False inside if x % i == 0 will break the loop as well as it will
return False to the function call which will indicate that the number in
question is not a prime number. At this time else clause  of for loop will
not work as the loop is broken due to Return False

If the number in question is a prime number, at that time the for loop will
fully  operate  or either will not even start(at the time when the number in
question is 2  or 3). In that case the else clause will  work and return
True will indicate that the number is prime

Just need to check if my understanding is correct or not .

Regards

Manprit Singh